AIEEE Questions

---

Meiosis ::

Meiosis is a type of cell division that reduces the chromosome number by half in daughter cells, creating four haploid cells, each genetically distinct from the parent cell that gave rise to them.

Why it is called as Reduction Division ::

1. As the Meiosis division process involves in reduction of chromosome number in the daughter cells to half the number in the parent cell, this process is called Reduction Division.
Meiosis creates gametes (egg and sperm cells).

2. The resulting gametes have 23 new chromosomes, one member of each of the 23 pairs, representing unique combinations of the original maternal and paternal copies.

Total quantity of sugar = 45 + 30 = 75

Gain or loss can be calculated as

9.75 x 75 - (30 x 9 + 45 x 10)

= 731.25 - 720

= 11.25

Hence, in the overall transaction, Rishi got Rs. 11.25 gain.

Let the side of the square be 's' cm

length of rectangle = (s+5) cm

breadth of rectangle = (s-3)cm

(s+5) (s-3) = 

s2 - 5s - 3s - 15 = s2 

2s = 15

Perimeter of rectangle = 2(L+B) = 2(s+5 + s–3) = 2(2s + 2)

= 2(15 + 2) = 34 cm 

IUPAC stands for International Union of Pure and Applied Chemistry.

A chemical nomenclature is a set of rules to generate systematic names for chemical compounds. The nomenclature used most frequently worldwide is the one created and developed by the International Union of Pure and Applied Chemistry (IUPAC).

Okhla Bird Sanctuary is located in Uttar Pradesh.

Okhla Bird Sanctuary is a bird sanctuary at the Okhla barrage over Yamuna River. It is situated in Noida, Gautam Buddh Nagar district, on Delhi-Uttar Pradesh state border and known as a haven for over 300 bird species.

Rate of her upstream = 12/2.5 = 4.8 km/hr

Then, ATQ

Rate of downstream = 4.8 x 3 = 14.4 km/hr

Hence, the distance she covers downstream in 5 hrs = 14.4 x 5 = 72 kms.

Let the speed of the train be 'S' kmph

From the given data,

Distance = Length of train = D = 200 mts = 200 x 18/5 kms

Time = 10 sec

given speed of the motorcycler = 12 kmph

Relative speed as they are moving in the same direction = (S - 12) kmph

$$\begin{gathered} (S- 12) = 200 x 18515 \\ S - 12 = 48 \\ S = 60 kmph \\ \end{gathered}$$

Hence, the speed of the train = S = 60 kmph

Now,

Let the speed of the jeep be 'x' kmph

$$\begin{gathered} 60 - x = 200 x 18520 \\ 60 - x = 36 \\ x = 60 - 36 \\ x = 24 kmph \end{gathered}$$

Therefore, the speed of the jeep = x = 24 kmph.