Bank Exams Questions

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Let the present age of the man be 'P' and son be 'Q',
Given, P + Q = 64 or Q = (64 - P)
Now the man says "I am five times as old as you were, when I was as old as you are",
So, P = 5[B - (P - Q)]
We get 6P = 10Q,
Substitute value for Q,
6P = 10(64 - P),
Therefore P = 40, Q = 24.

-4-(-10) = -4+10 = 6

-10-(-4) = -10+4= -6

Therefore, 6-(-6) = 6+6 = 12

Choose 1 person for the single room & from the remaining choose 2 for the double room & from the remaining choose 4 people for the four person room, 

 Then, ⁷C₁ x ⁶C₂ x ⁴C₄ 

_{= 7 x 15 x 1 = 105}

Let the number of sides be n. 

The number of diagonals is given by ⁿC₂ - n  

^{Therefore, n}C₂ - n = 44, n>0 

ⁿC₂ - n = 44

n² - 3n - 88 = 0 

n² -11n + 8n - 88 = 0  

As n>0, n will not be -8. Therefore, n=11.

The police ought to find out the lackenings in existing security arrangements and make up for these inadequacies to strengthen security and thus prevent criminal activities in the forthcoming festival. So, both a and b follow. Arresting the known criminals does not ensure safety, for a novice can also indulge in crime. So, c does not follow.

1. Answer (c)

Each time we order 1, one apple is added to the basket but each time when 4 is ordered, one apple is removed from it.

Required number of apples = number of 1's - number of 4's = 6 - 4 = 2

2. Answer (d)

Each time we order 1, 2 or 3, one fruit is added to the basket but when ever we order 4, two fruits are removed from it.

Required number = Number of 1's + Number of 2's + Number of 3's - 2 x (Number of 4's)

= 6 + 6 + 7 - (2x4)
= 19 - 8
= 11.

Clearly, we may mark such sets of 3 numbers, in which the middle number is 8 and each of the two numbers on both sides of it is a factor of 8, as shown below :

2 8 3 8 2 4 8 2 4 8 6 8 2 8 2 4 8 3 8 2 8 6

So, there are two such 8's. Hence the answer is C.