GATE Questions

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A can complete the work in 12 days working 8 hours a day

=> Number of hours A can complete the work = 12×8 = 96 hours 

=> Work done by A in 1 hour = 1/96

B can complete the work in 8 days working 10 hours a day

=> Number of hours B can complete the work = 8×10 = 80 hours 

=> Work done by B in 1 hour = 1/80

Work done by A and B in 1 hour = 1/96 + 1/80 = 11/480

 => A and B can complete the work in 480/11 hours

A and B works 8 hours a day.

Hence total days to complete the work with A and B working together 

= (480/11)/ (8) = 60/11 days

a. P's investment = (80000 x 6 + 60000 x 6) = 840000 for 1 month.

b & c. Q's investment = 80% of Rs. 60000 for 8 months.

= Rs.(48000 x 8) for 1 month = 384000 for 1 month

P : Q = 840000 : 384000 = 35 : 16.

But, the total profit is not given, so data is inadequate.

*  The Gulf of Mexico, bordered by the United States, Mexico, and the island nation of Cuba, is the worlds largest gulf.

*  It has a coastline of about 5,000 kilometers (3,100 miles).

*  The Gulf of Mexico is connected to the Atlantic Ocean by the Straits of Florida, between Cuba and the U.S. state of Florida.

*  It is largely surrounded by the North American continent.

Nutrients that are needed in large amounts are called Macronutrients.

There are three macronutrients required by humans:

1. carbohydrates (sugar),

2. lipids (fats), and

3. proteins.

Each of these macronutrients provides energy in the form of calories.

Some other macronutrients are: nitrogen (N), phosphorus (P), potassium (K), calcium (Ca), sulfur (S), magnesium (Mg), sodium (Na).

Let the distance he covered each way = d kms

According to the question,

d/45 - d/50 = 1

=> d = 450 kms.

Hence, the total distance he covered in his way = d + d = 2 d = 2 x 450 = 900 kms.

Covalent type of bonding joins The two hydrogen atoms are joned by Covalent type of bonding.

In this type of bonding, electrons are shared between the atoms in order to fill there valence shells. Thus sharing of electrons take place in between the hydrogen atoms.

Let 'Y' be the youngest player.

The last song can be sung by any of the remaining 3 players. The first 3 players can sing the song in (3!) ways.

The required number of ways = 3(3!) = 4320.