# Job Roles

A) I alone sufficient while II alone not sufficient to answer | B) II alone sufficient while I alone not sufficient to answer |

C) Either I or II alone sufficient to answer | D) Both I and II are not sufficient to answer |

Explanation:

We know that, R = (100 x S.I) / (P x T)

Now I gives, S.I = Rs. 4000.

II gives, T = 4 years.

But, P is unknown. So, we cannot find R.

So, given data is insufficient to get R.

A) I alone sufficient while II alone not sufficient to answer | B) II alone sufficient while I alone not sufficient to answer |

C) Either I or II alone sufficient to answer | D) Both I and II are necessary to answer |

Explanation:

Let the rate be R% p.a.

I gives, P = Rs. 8000 and T = 4 years.

II gives, S.I = Rs. (8800 - 8000) = Rs. 800.

R = [100 x S.I] / [p x t ]= (100 x 800)/(8000 x 4) = 2 ½ % p.a

Thus, I and II both are needed to get the answer.

A) 65years | B) 56years |

C) 45years | D) 57years |

Explanation:

Simple interest is given by the formula SI = (pnr/100), where p is the principal, n is the numberof years for which it is invested, r is the rate of interest per annum

In this case, Rs. 1250 has become Rs.10,000.

Therefore, the interest earned = 10,000 – 1250 = 8750.

8750 = [(1250 x n x 12.5)/100]

=> n = 700 / 12.5 = 56 years.

A) 25years | B) 15years |

C) 20years | D) 22years |

Explanation:

From the information provided we know that,

Principal + 8% p.a. interest on principal for n years = 180 …….. (1)

Principal + 4% p.a. interest on principal for n years = 120 ……… (2)

Subtracting equation (2) from equation (1), we get

4% p.a. interest on principal for n years = Rs.60.

Now, we can substitute this value in equation (2),

i.e Principal + 60 = 120

= Principal = Rs.60.

We know that SI = , where p is the principal, n the number of years and r the rate percent of interest.

In equation (2), p = Rs.60, r = 4% p.a. and the simple interest = Rs.60.

Therefore, 60 =(60*n*4)/100

=> n = 100/4 = 25 years.

A) Rs.4000 | B) Rs.9000 |

C) Rs.5000 | D) Rs.6000 |

Explanation:

Let sum = P and original rate = R. Then

[(P * (R+2) * 3)/100] - [ (P * R * 3)/100] = 360

3P*(R+2) - 3PR = 36000

3PR + 6P - 3PR = 36000

6P = 36000

P = 6000

A) 12.5% | B) 13.5% |

C) 11.5% | D) 14.5% |

Explanation:

Let principal = P, Then, S.I.= P and Time = 8 years

We know that S.I. = PTR/100

**Rate** = [(100 x P)/ (P x 8)]% = 12.5% per annum.

A) Rs.1625 | B) Rs1525 |

C) Rs.1425 | D) Rs.1325 |

Explanation:

Let sum be Rs.x then, S.I. =Rs. [ x * (27/2) * 4 * (1/100) ] = Rs. 27x/50

Amount =Rs [ x + (27x/50)] = Rs.77x/50

=> 77X/50 = 2502.50

=>X= (2502.50 * 50)/77 = 1625

Hence Sum = Rs.1625

A) 118 | B) 105 |

C) 108 | D) 110 |

Explanation:

(24 + 31 + 18) days = 73 days = 1/5 year .

P = Rs 3000 and R = 18 % p.a.

$S.I=\left(\raisebox{1ex}{$3000*18*{\displaystyle \frac{1}{5}}$}\!\left/ \!\raisebox{-1ex}{$100$}\right.\right)$