# Job Roles

• #### Software Architect

Q:

What is the rate of simple interest?
I. The total interest earned was Rs. 4000.
II. The sum was invested for 4 years.

 A) I alone sufficient while II alone not sufficient to answer B) II alone sufficient while I alone not sufficient to answer C) Either I or II alone sufficient to answer D) Both I and II are not sufficient to answer

Explanation:

We know that, R = (100 x S.I) / (P x T)

Now I gives, S.I = Rs. 4000.

II gives,  T = 4 years.

But, P is unknown. So, we cannot find R.

So, given data is insufficient to get R.

0 3896
Q:

What percentage of simple interest per annum did Anand pay to Deepak?
I. Anand borrowed Rs. 8000 from Deepak for four years.
II. Anand returned Rs. 8800 to Deepak at the end of two years and settled the loan

 A) I alone sufficient while II alone not sufficient to answer B) II alone sufficient while I alone not sufficient to answer C) Either I or II alone sufficient to answer D) Both I and II are necessary to answer

Explanation:

Let the rate be R% p.a.

I  gives, P = Rs. 8000 and T = 4 years.

II gives, S.I = Rs. (8800 - 8000) = Rs. 800.

R = [100 x S.I] / [p x t ]= (100 x 800)/(8000 x 4) = 2 ½ % p.a

Thus, I and II both are needed to get the answer.

1 4607
Q:

How long will it take for a sum of money to grow from Rs.1250 to Rs.10,000, if it is invested at 12.5% p.a simple interest?

 A) 65years B) 56years C) 45years D) 57years

Explanation:

Simple interest is given by the formula SI = (pnr/100), where p is the principal, n is the numberof years for which it is invested, r is the rate of interest per annum

In this case, Rs. 1250 has become Rs.10,000.

Therefore, the interest earned = 10,000 – 1250 = 8750.

8750 = [(1250 x n x 12.5)/100]

=> n = 700 / 12.5 = 56 years.

14 11315
Q:

A sum of money invested for a certain number of years at 8% p.a. simple interest grows to Rs.180. The same sum of money invested for the same number of years at 4% p.a. simple interest grows to Rs.120 only. For how many years was the sum invested?

 A) 25years B) 15years C) 20years D) 22years

Explanation:

From the information provided we know that,

Principal + 8% p.a. interest on principal for n years = 180 …….. (1)

Principal + 4% p.a. interest on principal for n years = 120 ……… (2)

Subtracting equation (2) from equation (1), we get

4% p.a. interest on principal for n years = Rs.60.

Now, we can substitute this value in equation (2),

i.e Principal + 60 = 120

= Principal = Rs.60.

We know that SI = , where p is the principal, n the number of years and r the rate percent of  interest.

In equation (2), p = Rs.60, r = 4% p.a. and the simple interest = Rs.60.

Therefore, 60 =(60*n*4)/100

=> n = 100/4 = 25 years.

6 9818
Q:

A sum was put at simple interest at a certain rate for 3 years. Had it been put at 2% higher rate, it would have fetched Rs 360 more. Find the sum.

 A) Rs.4000 B) Rs.9000 C) Rs.5000 D) Rs.6000

Explanation:

Let sum = P and original rate = R. Then

[(P * (R+2) * 3)/100] - [ (P * R * 3)/100] = 360

3P*(R+2) - 3PR = 36000

3PR + 6P - 3PR = 36000

6P = 36000

P = 6000

23 15541
Q:

At what rate percent per annum will a sum of money double in 8 years.

 A) 12.5% B) 13.5% C) 11.5% D) 14.5%

Explanation:

Let principal = P, Then, S.I.= P and Time = 8 years

We know that S.I. = PTR/100

Rate = [(100 x P)/ (P x 8)]% = 12.5% per annum.

130 34058
Q:

A sum at simple interest at $1312$% per annum amounts to Rs. 2502.50 after 4 years. Find the sum

 A) Rs.1625 B) Rs1525 C) Rs.1425 D) Rs.1325

Explanation:

Let sum be Rs.x then, S.I. =Rs. [ x * (27/2) * 4 * (1/100) ] = Rs. 27x/50

Amount =Rs [ x + (27x/50)] = Rs.77x/50

=> 77X/50 = 2502.50

=>X= (2502.50 * 50)/77 = 1625

Hence Sum = Rs.1625

5 6036
Q:

Find: S.l. on Rs 3000 at 18% per annum for the period from 4th

 A) 118 B) 105 C) 108 D) 110

Explanation:

(24 + 31 + 18) days = 73 days = 1/5 year .

P = Rs 3000 and R = 18 % p.a.

$S.I=3000*18*15100$