Analyst Questions


Q:

Solve this inequality 3p - 16 < 20?

A) p >= 12 B) p <= 11/3
C) p < 12 D) p > 11/3
 
Answer & Explanation Answer: C) p < 12

Explanation:

The given inequality is 3p - 16 < 20

For solving this inequality, follow these steps

Now add 16 on both sides

we get 3p - 16 + 16 < 20 + 16

=> 3p  < 36

Now divide the above eqn with 3 on both sides

we get, 3p/3 < 36/3

p < 12.

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Q:

What is the bond order of O2?

A) 1.5 B) 2
C) 2.5 D) 1
 
Answer & Explanation Answer: B) 2

Explanation:

The number of bonds between a pair of atoms is called the bond order.

Bond orders can be calculated from Lewis structures, which are the heart of the valence-bond model. Oxygen, for example, has a bond order of two.

Structure

When there is more than one Lewis structure for a molecule, the bond order is an average of these structures. The bond order in sulfur dioxide, for example, is 1.5  the average of an S-O single bond in one Lewis structure and an S=O double bond in the other.

Structures

In molecular orbital theory, we calculate bond orders by assuming that two electrons in a bonding molecular orbital contribute one net bond and that two electrons in an antibonding molecular orbital cancel the effect of one bond. We can calculate the bond order in the O2 molecule by noting that there are eight valence electrons in bonding molecular orbitals and four valence electrons in antibonding molecular orbitals in the electron configuration of this molecule. Thus, the bond order is two.

Equation

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1 4047
Q:

A paper written by hand

A) Thesis B) Handicraft
C) Manuscript D) Handiwork
 
Answer & Explanation Answer: C) Manuscript

Explanation:

A paper written by hand are called as Manuscripts.

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1 4046
Q:

Which nitrogenous base is not found in dna?

A) Uracil B) Thymine
C) Cytosine D) Guanine
 
Answer & Explanation Answer: A) Uracil

Explanation:

A nitrogenous base, or nitrogen-containing base, is an organic molecule with a nitrogen atom that has the chemical properties of a base. The main biological function of a nitrogenous base is to bond nucleic acids together. A nitrogenous base owes its basic properties to the lone pair of electrons of a nitrogen atom.

 

In DNA, four bases have been found. They are

1. Adenine (A),

2. Guanine (G),

3. Cytosine (C) and

4. Thymine (T).

 

The first three of these bases are found in RNA also but the fourth which is Uracil (U) is absent in it.

RNA contains cytosine and uracil as pyrimidine bases while DNA has cytosine and thymine.

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Filed Under: Biology
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4 4042
Q:

The New Deal ended in 1938 partly because

A) national concern shifted to overseas aggression B) FDR was defeated in his bid for reelection
C) the Supreme Court ruled most New Deal programs unconstitutional D) FDR was stricken with polio
 
Answer & Explanation Answer: A) national concern shifted to overseas aggression

Explanation:

The New Deal was a series of programs, public work projects, financial reforms and regulations enacted in the United States 1933-36, in response to the Great Depression organized by Franklin Roosevelt in US.

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Q:

What is x squared plus x squared?

A) 4x B) 2x^2
C) x^4 D) 2x
 
Answer & Explanation Answer: B) 2x^2

Explanation:

In an algebraic expression, like terms are terms that contain the same variables raised to the same powers. Calculating x-squared plus x-squared is a matter of combining like terms. 

Now x^2 + x^2 = 2x^2

 

Hence, x-squared plus x-squared is equal to 2 times x squared.

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Filed Under: Mathematical Operations
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Q:

In the given number series which follows the definite rules then find out the value of (M, N, O, and P) in second number series.

7  18  42  94  204

4   M   N    O     P

What value will come in place of P?

A) 179 B) 184
C) 164 D) 156
 
Answer & Explanation Answer: D) 156

Explanation:

Here the given series 7  18  42  94  204 follows a pattern that, 

7

×2+4 = 18

18 ×2+6 = 42

42 ×2+10 = 94

94 ×2+16 = 204

Similarly,

4

×2+4 = 12

12 ×2+6 = 30

30 ×2+10 = 70

70 ×2+16 = 156

Hence, the value of P = 156.

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8 4038
Q:

A certain sum is invested for 2 years in scheme M at 20% p.a. compound interest (compounded annually), Same sum is also invested for the same period in scheme N at k% p.a. simple interest. The interest earned from scheme M is twice of that earned from scheme N. What is the value of k?

A) 7 B) 11
C) 9 D) 13
 
Answer & Explanation Answer: B) 11

Explanation:

Interest earned in scheme M =   

P1 + 201002  - 1  = 11P25

Interest earned in scheme N =  

P x k x 2100 = Pk50

 

Now, from the given data,

 

11P25 = 2 x Pk50

k = 11

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Filed Under: Compound Interest
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20 4036