Bank Clerk Questions


Q:

Lucky started working 2 years ago. Her starting salary was half of Karthik's salary at that time. Each year since then Lucky and Karthik have received a rise of 10% in their respective salary. What percentage (to the nearest percent) of Karthik's current salary is Lucky's current salary ?

A) 75% B) 22.5%
C) 35% D) 50%
 
Answer & Explanation Answer: D) 50%

Explanation:

Let the salary of Karthik 2 years ago be Rs.100
So, Lucky's salary 2 years ago was Rs.50

 

Karthik's present salary has seen two 10 percent increases. So as Lucky's salary.

So, Karthik's salary 1 year ago = 100 + 10% of 100 = 100 + 10 = 110.
Karthik's present salary = 110 + 10% of 110 = 110 + 11 = 121.

 

Lucky's salary 1 year ago = 50 + 10% of 50 = 50 + 5 = 55
Lucky's present salary = 55 + 10% of 55 = 55 + 5.5 = 60.5

 

Lucky's present salary of 60.5 = 50% of Karthik's present salary of 121.

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Filed Under: Percentage
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Job Role: Bank PO , Bank Clerk

20 8615
Q:

43% of 616.6 + 37% of 217 =?

A) 345.428 B) 354.428
C) 344.428 D) 364.428
 
Answer & Explanation Answer: A) 345.428

Explanation:

43 x 616.6/100 + 37 x 217/100

=> 265.138 + 80.29

=>  345.428

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Filed Under: Simplification
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2 8603
Q:

P, Q and R start simultaneously from A to B. P reaches B, turns back and meet Q at a distance of 11 km from B. Q reached B, turns back and meet R at a distance of 9 km from B. If the ratio of the speeds of P and R is 3:2, what is the distance between A and B ?

A) 99 B) 100
C) 89 D) 1
 
Answer & Explanation Answer: A) 99

Explanation:

Let, Distance between A and B = d

 

Distance travelled by P while it meets Q = d + 11

 

Distance travelled by Q while it meets P = d – 11

 

Distance travelled by Q while it meets R = d + 9

 

Distance travelled by R while it meets Q = d – 9

 

Here the ratio of speeds of P & Q => SP : SQ = d + 11 : d – 11

 

The ratio of speeds of Q & R => SQ : SR = d + 9 : d – 9

 

But given Ratio of speeds of P & R => P : R = 3 : 2

 SPSR = SPSQxSQSR = d+11d+9d-11d-9

 

=> d+11d+9d-11d-9 = 3/2

 

=>  d = 1, 99

 

=> d = 99 satisfies.

 

Therefore, Distance between A and B = 99

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Filed Under: Time and Distance
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16 8601
Q:

If a soldier fires 7 shots from a gun in 12 minutes then find the total number of shots fired by the man in 3/2 hrs.

A) 45 B) 44
C) 46 D) 47
 
Answer & Explanation Answer: C) 46

Explanation:

Here given soldier shots 7 shots in 12 min

=> 1 shot doen't take any time in 12 min 

=> Only 6 shots take 12 min 

12 min ------ 6 shots 

90 min ------ ? shots 

=> 90 x (6/12) = 45 

Therefore, total shots fired in 90 minutes = 45 + 1 = 46 shots.

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11 8599
Q:

Which of the following pairs have the same relationship as OFTEN : FOTEN?

A) HEART : TRAHE B) OPENS : SNEOP
C) RISKY : IRSYK D) FIRST : IFRST
 
Answer & Explanation Answer: C) RISKY : IRSYK

Explanation:

      It is a case of shifting as given below:

 

      1  2  3  4  5                    2  1  3  5  4

 

      O  F  T  E  N     F  O  T  N  E

 

---------------------------------------------------------------------------

 

       1  2  3  4  5                   5  4  3  1  2

 

1.    H  E  A  R  T             T  R  A  H  E    

 

2.    O  P  E  N  S    S  N  E  O  P

 

        1  2  3  4  5         2  1  3  5  4

3.    R  I  S  K  Y     I  R  S  Y  K

 

 

4.    F  I  R  S  T     I  F  R  S  T

 

Hence option 3 is correct.

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Filed Under: Analogy
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19 8588
Q:

Which expression is equivalent to i233?

A) i B) 1
C) -i D) -1
 
Answer & Explanation Answer: A) i

Explanation:

We know that,

i2 = -1i3 = i2 x i = -1 x i = -ii4 = i2 x i2 = -1 x -1 = 1Hence, i233  =i4 x 58 + 1 = i232 x i1 = 1 x i = i

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Filed Under: Numbers
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9 8583
Q:

Find the wrong number from the following series ?
7   18   40   106   183   282   403

A) 18 B) 183
C) 40 D) 106
 
Answer & Explanation Answer: C) 40

Explanation:

The given series follows the rule,
+(11x1), +(11x3), +(11x5), +(11x7), +(11x9),....

So starting from 7, 7 + 11 = 18, 18 + 33 = 51, 51 + 55 = 106, ...
So wrong number is 40 which is to be 51.

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Filed Under: Number Series
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11 8575
Q:

Which compound contains both ionic and covalent bonds?

A) NaNO3 B) CaSO4
C) NH4Cl D) All of the above
 
Answer & Explanation Answer: D) All of the above

Explanation:

Here all the given compounds have both ionic and covalent bonds.

 

NaNO3 - In Sodium nitrate, Nitrate is covalently bonded as nitrogen is bonded with 3 oxygen atoms. And this nitrate is ionically bonded with sodium.

 

CaSO4 - In Calcium sulphate, sulphate is covalently bonded as sulphur is bonded with 4 oxygen atoms. And this sulphate is ionically bonded with calcium.

 

NH4Cl - In Ammonium chloride, ammonium is covalently bonded as nitrogen is bonded with 4 hydrogen atoms. And this ammonium is ionically bonded with chlorine.

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Filed Under: Chemistry
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5 8574