A) 99 | B) 100 |

C) 89 | D) 1 |

Explanation:

Let, Distance between A and B = d

Distance travelled by P while it meets Q = d + 11

Distance travelled by Q while it meets P = d – 11

Distance travelled by Q while it meets R = d + 9

Distance travelled by R while it meets Q = d – 9

Here the ratio of speeds of P & Q => SP : SQ = d + 11 : d – 11

The ratio of speeds of Q & R => SQ : SR = d + 9 : d – 9

But given Ratio of speeds of P & R => P : R = 3 : 2

$\frac{SP}{SR}=\frac{SP}{SQ}x\frac{SQ}{SR}=\frac{\left(d+11\right){\displaystyle \left(d+9\right)}}{\left(d-11\right){\displaystyle \left(d-9\right)}}$

=> $\frac{\left(d+11\right)\left(d+9\right)}{\left(d-11\right)\left(d-9\right)}$ = 3/2

=> d = 1, 99

=> d = 99 satisfies.

Therefore, Distance between A and B = 99

A) 160 km/h | B) 200 km/h |

C) 150 km/h | D) 100 km/h |

A) 6.5 km/h | B) 4.5 km/h |

C) 7.5 km/h | D) 5.5 km/h |

A) 12 hours | B) 23 hours |

C) 17 hours | D) 18 hours |

A) 720 m | B) 460 m |

C) 360 m | D) 620 m |

A) 5.4 km/h | B) 6.9 km/h |

C) 3.6 km/h | D) 4.8 km/h |