Bank PO Questions

Assume x soldiers join the fort. 1200 soldiers have provision for 1200 (days for which provisions last them)(rate of consumption of each soldier)
= (1200)(30)(3) kg.

Also provisions available for (1200 + x) soldiers is (1200 + x)(25)(2.5) k

As the same provisions are available
=> (1200)(30)(3) = (1200 + x)(25)(2.5)

x = ([(1200)(30)(3)] / (25)(2.5)) - 1200 => x = 528.

In India, Fiscal Policy is formulated by the Ministry of Finance.

Fiscal policy is playing an important role on the economic and social front of a country. Traditionally, fiscal policy is concerned with the determination of state income and expenditure policy. But with the passage of time, the importance of fiscal policy has been increasing continuously for attaining rapid economic growth.

An effective fiscal policy is composed of policy decisions relating to the entire financial structure of the government including tax revenue, public expenditures, loans, transfers, debt management, budgetary deficit, etc.

We know that the day repeats after every seven days. 

Given that first day of the month is Tuesday

i.e    1st - Tuesday

1+7 = 8 - Tuesday

8+7 =15- Tuesday

15+7=22-Tuesday

22+7=29-Tuesday

But given that last day of the same month is Monday

It is possible only in he month of Febuary with 28 days.

Let length = x meters, then breadth = 0.6x 

Given that  perimeter = 800 meters 

=> 2[ x + 0.6x] = 800 

=> x = 250 m 

Length = 250m and breadth = 0.6 x  250 = 150m 

Area = 250 x 150 = 37500 sq.m

LCM of 2, 3, 7 is 42.

=> (700 – 300)/42 = 9  22/42 => 9 Numbers.

distance covered in 1 revolution = 2πr = 2 x (22/7) x 20 = 880/7 cm
required no of revolutions = 17600 x (7/880) = 140

Let the present ages of Ajay and Vijay be 'A' and 'V' years respectively.

=> A - 8 = 4/3 (V - 8) and A + 8 = 6/5 (V + 8)

=> 3/4(A - 8) = V - 8 and 5/6(A + 8) = V + 8

V = 3/4 (A - 8) + 8 = 5/6 (A + 8) - 8

=> 3/4 A - 6 + 8 = 5/6 A + 20/3 - 8

=> 10 - 20/3 = 10/12 A - 9/12 A

=> 10/3 = A/12 => A = 40.

Side of smallest cube = L.C.M of 5, 10, 20 = 20cm  

Volume of the cube = (20 x 20 x 20)cu.cm = 8000 cu.cm  

Volume of the block= (5 x 10 x 20)cu.cm = 1000 cu.cm  

Number of blocks = (8000/1000) = 8