Bank PO Questions


Q:

There are 3 sections with 5 questions each. If four questions are selected from each section, the chance of getting different questions is ?

A) 1000 B) 625
C) 525 D) 125
 
Answer & Explanation Answer: D) 125

Explanation:

Methods for selecting 4 questions out of 5 in the first section = 5 x 4 x 3 x 2 x 1/4 x 3 x 2 x 1 = 5. Similarly for other 2 sections also i.e 5 and 5


So total methods = 5 x 5 x 5 = 125.

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Filed Under: Permutations and Combinations
Exam Prep: GRE , GATE , CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk

4 4893
Q:

Bind it and it walks, Loose it and it stops. What is it?

Answer

A Sandal.


It has sticking strips to make them fit for our feet. If you bind them only you can start walking or other wise it comes out.

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7 4892
Q:

Find the lowest common multiple of 24, 36 and 40?

A) 360 B) 420
C) 240 D) 120
 
Answer & Explanation Answer: A) 360

Explanation:

To find the LCM of 24, 36 and 40

24 = 2 x 2 x 2 x 3

36 = 2 x 2 x 3 x 3

40 = 2 x 2 x 2 x 5 

Now, LCM of 24, 36 and 40 = 2 x 2 x 2 x 3 x 3 x 5

= 8 x 9 x 5

= 72 x 5

= 360

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Filed Under: HCF and LCM
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Analyst , Bank Clerk , Bank PO

19 4891
Q:

Parallel construction means that you

A) give both sides of the argument in your essay. B) begin each paragraph of your essay in the same way.
C) use the same grammatical construction in all similar headings throughout an outline. D) repeat the first paragraph of your essay as the last paragraph.
 
Answer & Explanation Answer: C) use the same grammatical construction in all similar headings throughout an outline.

Explanation:
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Filed Under: Alphabet Test
Exam Prep: AIEEE , Bank Exams , GRE , TOEFL
Job Role: Analyst , Bank Clerk , Bank PO

16 4889
Q:

Arun has certain number of books. It is not less than 15 and not more than 30. If he wants to give these books equally to 2 of his friends, then 1 book will remain. If he wants to give these books equally to 3 of his friends, then 2 books will remain. If he wants to give these books equally to 4 of his friends, then 3 books will remain. What is the number of books he had ?

A) 19 B) 23
C) 17 D) 15
 
Answer & Explanation Answer: B) 23

Explanation:

If he wants to give these books equally to 2 of his friends, then 1 book will remain, it means possible number of books = 15,17,19,21,23,25,27,29
If he wants to give these books equally to 3 of his friends, then 2 books will remain, it means possible number of books = 17,20,23,26,29
If he wants to give these books equally to 4 of his friends, then 3 book will remain, it means possible number of books = 15,19,23,27
common number is only 23 so it will be answer

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Filed Under: Numbers
Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Bank Clerk , Bank PO

4 4887
Q:

The newly appointed adviser to Odsha government on public health programmes, K. Srinath Reddy is the receiver of which prestigious civilian award ?

A) Padma Vibushan B) Padma Shri
C) Padma Bhushan D) Bharat Ratna
 
Answer & Explanation Answer: C) Padma Bhushan

Explanation:
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Filed Under: Honours and Awards
Exam Prep: Bank Exams , CAT
Job Role: Bank PO

2 4886
Q:

If two cards are taken one after another without replacing from a pack of 52 cards. What is the probability for the two cards be Ace ?

A) 51/1221 B) 42/221
C) 1/221 D) 52/1245
 
Answer & Explanation Answer: C) 1/221

Explanation:

Total Combination of getting a card from 52 cards = C152

Because there is no replacement, so number of cards after getting first card= 51

Now, Combination of getting an another card= C151


Total combination of getting 2 cards from 52 cards without replacement= (C152×C151


There are total 4 Ace in stack. Combination of getting 1 Ace is = C14

 

Because there is no replacement, So number of cards after getting first Ace = 3


Combination of getting an another Ace = C13

Total Combination of getting 2 Ace without replacement=C14×C13

Now,Probability of getting 2 cards which are Ace =C14×C13C152×C151 = 1/221.

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Filed Under: Permutations and Combinations
Exam Prep: CAT , Bank Exams , AIEEE
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5 4886
Q:

Out of 3 girls and 6 boys a group of three members is to be formed in such a way that at least one member is a girl. In how many different ways can it be done?

A) 64 B) 84
C) 56 D) 20
 
Answer & Explanation Answer: A) 64

Explanation:

Total number of possible ways = 9C3 = 84 ways

Required atleast one girl in the group of three = total possible ways - ways in which none is girl

None of the members in the group is girl = 6C3 = 20

 

Therefore, number of ways that at least one member is a girl in the group of three

= 84 - 20

= 64 ways.

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Filed Under: Probability
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