Database Administration Questions

Total work is given by L.C.M of 72, 48, 36

Total work = 144 units

Efficieny of A = 144/72 = 2 units/day

Efficieny of B = 144/48 = 3 units/day

Efficieny of C = 144/36 = 4 units/day

According to the given data,

2 x p/2 + 3 x p/2 + 2 x (p+6)/3 + 3 x (p+6)/3 + 4 x (p+6)/3 = 144 x (100 - 125/3) x 1/100

3p + 4.5p + 2p + 3p + 4p = 84 x 3 - 54

p = 198/16.5

p = 12 days.

Now, efficency of D = (144 x 125/3 x 1/100)/10 = 6 unit/day

(C+D) in p days = (4 + 6) x 12 = 120 unit

Remained part of work = (144-120)/144 = 1/6.

The collections of entities of a particular Entity Type are grouped together into an entity set.

We park car temporarily in garrage, similarly, aeroplane is temporarily parked in hangar.

The path traced by planet is called Orbit. Similarly, the path traced by projectile is called Trajectory.

Hence, Planet : Orbit : : Projectile : Trajectory.

Required probability is given by P(E) = n(E)n(S) = 14C2 = 16

CPU speed is the central factor in a computer's performance. And this CPU speed depends on the processor in the CPU chip. In a computer, clock speed refers to the number of pulses per second generated by an oscillator that sets the tempo for the processor. Clock speed is usually measured in Hertz (Hz).

But now-a-days, a pure processor's performance is measured in MIPS (Millions of Instructions Per Second). As here in the question, how a processor's speed is measured is asked and it is Hertz. 

Hence, Processor's speed of a computer is measured in Hertz(Hz) [MHz, GHz].

Speeds of two trains = 30 kmph and 58 kmph

=> Relative speed = 58 - 30 = 28 kmph = 28 x 5/18 m/s = 70/9 m/s

Given a man takes time to cross length of faster train = 18 sec

Now, required Length of faster train = speed x time = 70/9  x  18 = 140 mts.