Solve the equation 122x+1 = 1 ?
Rewrite equation as 122x+1 = 120
Leads to 2x + 1 = 0
Solve for x : x = -1/2
If log72 = m, then log4928 is equal to ?
log4928 = 12log77×4
= 12+122log72= 12+log72= 12 + m= 1+2m2.
If a2+b2 = c2 , then 1logc+ab + 1logc-ab = ?
Given a2 + b2 = c2
Now 1logc+ab + 1logc-ab
= logbc+a + logbc-a
= 2logbb = 2
If log 64 = 1.8061, then the value of log 16 will be (approx)?
Given that, log 64 = 1.8061
--> 3 log 4 = 1.8061
--> log 4 = 0.6020
--> 2 log 4 = 1.2040
Therefore, log 16 = 1.2040
A fast moving superfast express crosses another pasenger train in 20 seconds. The speed of faster train is 72 km/hr and speeds of slower train is 27 km/h. Also the length of faster ntrain is 100m, then find the length of the slower train if they are moving in the same direction.
Time=Sum of length of the two trainsDifference in speeds
For x∈N, x>1, and p=logxx+1, q=logx+1x+2 then which one of the following is correct?
kl>k+1l+1 for (k,l) > 0 and k > l
Let k = x+1 and l = x
(x + 1) > x
The Value of logtan10+logtan20+⋯⋯+logtan890 is
= log tan10+log tan890 + log tan20+ log tan880+⋯⋯+log tan450
= log [tan10 × tan890] + log [tan20 × tan880 ] +⋯⋯+log1
∵ tan(90-θ)=cotθ and tan 450=1
= log 1 + log 1 +.....+log 1
What is the number of digits in 333? Given that log3 = 0.47712?
Let Let x=333 = 333
Then, logx = 33 log3
= 27 x 0.47712 = 12.88224
Since the characteristic in the resultant value of log x is 12
∴The number of digits in x is (12 + 1) = 13
Hence the required number of digits in 333is 13.
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