Questions

A tertiary consumer is an animal that obtains its nutrition by eating primary consumers and secondary consumers.

Usually tertiary consumers are carnivorous predators, although they may also be omnivores, which are animals that feed on both meat and plant material.

Tertiary consumers often occupy the top trophic level, and so are predated by no other animals; in this case they are called "apex predators". However, when they die their bodies will be consumed by scavengers and decomposers.

Being submissive to somebody is to acknowledge somebody to be in a greater authority than you are.

Submissive mean in a relationship is you obey that person without complaining or arguing about it.

In short, a submissive is a person who enjoys giving control of themselves to their life partners.

One way is shorting the two inputs of the NAND gate and passing the input.

truth table:

A B output

1 1 0

0 0 1

The second way is passing the input to only one input (say A) of the NAND gate. Since the other input  (say B is floating, it is always logic one.

Truth table:

A B output

1 1 0 

0 1 1

5 F on a H is a letter equation which indicates that 5 Fingers on a hand.

The project details and description will usually have less detail at the beginning of the project and will increase as the characteristics are progressively elaborated. Answer A is incorrect because the team should confirm that they understand the esence of the scope of the project, even if the details might be ambiguous at the beginning of the project. Answer B is incorrect because the project should go forward; however, the team should request further clarification of what the project scope entails. Answer D is incorrect because the project selection criteria should be established before the project begins.

#include "alloc.h"

#define MAXROW 3

#define MAXcol 4

main()

{

        int *p, i, J;

        p = (int *) malloc (MAXROW * MAXCOL * sizeof (int));

         for ( i=0; i < MaxROW ; i++)

         {

                for (j=0; j < MAXCOL ; j++)

                { 

                      p [ i * MAXCOL + j] = i;

                       printf ( "%d", p [i * MAXCOL + j] );

                 }

                  printf ("\n");

          }

}