Sawaal
301
Q:

(51 + 52 + 53 + .........+100) is equal to 

Answer:



51 + 52 + 53 + ...........+ 100


 = (1 + 2 + 3 + .... + 100) - (1 + 2 + 3 + ...... + 50)


 = It is in the form of n(n+1)2 series summation


= n1 = 100 , n2 = 50


=100100+12 - 5050+12


 =  (5050 - 1275) = 3775
Filed Under: Numbers - Quantitative Aptitude - Arithmetic Ability
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