6
Q:
| A) 2(6!) | B) 6! x 7 |
| C) 6! x ⁷P₆ | D) None |
Answer: C) 6! x ⁷P₆
Explanation:
Explanation:
We can initially arrange the six boys in 6! ways.
Having done this, now three are seven places and six girls to be arranged. This can be done in ⁷P₆ ways.
Hence required number of ways = 6! x ⁷P₆
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