|A) (1/2)^11||B) (9)(1/2)|
|C) (11C2)(1/2)^9||D) (1/2)|
Probability of occurrence of an event,
P(E) = Number of favorable outcomes/Numeber of possible outcomes = n(E)/n(S)
⇒ Probability of getting head in one coin = ½,
⇒ Probability of not getting head in one coin = 1- ½ = ½,
All the 11 tosses are independent of each other.
∴ Required probability of getting only 2 times heads =