97
Q:

# A letter is takenout at random from 'ASSISTANT'  and another is taken out from 'STATISTICS'. The probability that they are the same letter is :

 A) 35/96 B) 19/90 C) 19/96 D) None of these

Answer:   B) 19/90

Explanation:

$ASSISTANT→AAINSSSTT$

$STATISTICS→ACIISSSTTT$

Here N and C are not common and same letters can be A, I, S, T. Therefore

Probability of choosing A =  $2C19C1×1C110C1$ = 1/45

Probability of choosing I = $19C1×2C110C1$ = 1/45

Probability of choosing S = $3C19C1×3C110C1$ = 1/10

Probability of choosing T = $2C19C1×3C110C1$ = 1/15

Hence, Required probability =

Subject: Probability
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Q:

Find the range and mode of the data 17, 18, 28, 19, 16, 18, 17, 29, 18

 A) 12 and 18 B) 13 and 18 C) 12 and 17 D) 11 and 17

Answer & Explanation Answer: B) 13 and 18

Explanation:
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10 751
Q:

Find the standard deviation of {11, 7, 10,13, 9}

 A) 1 B) 2 C) 4 D) 5

Answer & Explanation Answer: B) 2

Explanation:
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2 600
Q:

A table tennis player, lost 12 games out of 18 games played. Calculate the games won in terms of decimal.

 A) 0.667 B) 0.067 C) 0.50 D) 0.333

Answer & Explanation Answer: D) 0.333

Explanation:
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2 646
Q:

A sequence , has odd number of terms. Then the median is

 A) axn2+1 B) axn2-1 C) axn-1 D) axn2

Answer & Explanation Answer: D) axn2

Explanation:
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3 4550
Q:

The mean of a distribution is 15 and the standard deviation is 5. What is the value of the coefficient variation?

 A) 16.66% B) 66.66% C) 33.33% D) 100%

Answer & Explanation Answer: C) 33.33%

Explanation:
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5 799
Q:

If the standard deviation of a population is 3, what would be the population variance?

 A) 9 B) 6 C) 8 D) 15

Answer & Explanation Answer: A) 9

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4 4922
Q:

The variance of a set of data is 169. Then the standard deviation of the data is

 A) +-13 B) 13 C) 69 D) 84.5

Answer & Explanation Answer: B) 13

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3 4102
Q:

If the standard deviation of a population is 10, what would be the population variance?

 A) 100 B) 30 C) 5 D) 20

Answer & Explanation Answer: A) 100

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4 796