A) 1:2 | B) 2:1 |

C) 11:24 | D) 36:121 |

Explanation:

**Compounded Ratio ::** When we compound two or more ratio's with each other through product or multiplication, the result is simply a compound ratio.

Thus, the product of two or more ratios; i.e, **ab:cd** is a ratio compounded of the simple ratios **a:c **and** b:d.**

Required compounded ratio = (2/3** x** 6/11 **x** 11/2) = **2/1. **

A) 196 | B) 148 |

C) 132 | D) 112 |

Explanation:

16 : 56 :: 32 : ?

Let the required number be **'n'**

The given numbers follow a logic that,

16/56 = 2/7

=> 32/n = 2/7

=> 32 x 7/2 = n

=> n = 112.

Hence, **16 : 56 :: 32 : 112.**

A) Rs. 571.25 | B) Rs. 175.5 |

C) Rs. 751.75 | D) Rs. 850 |

Explanation:

Let the price of required variety = Rs. P/kg

Then, respective amounts were m kg, m kg and 2m kg

= 126m + 135m + 2pm = 153 x 4m

=> 2p = 351

**p = 175.5 / kg**

A) 154 | B) 135 |

C) 112 | D) 106 |

Explanation:

From the given data,

Virat : Rohit = 3 : 2

Rohit : Dhoni = 3 : 2

Ratio of runs scored by Virat, Rohit and Dhoni respectively

= 3 x 3 : 2 x 3 : 2 x 2

9 : 6 : 4

Runs scored by Virat =** 9/19 x 285 = 135.**

A) 10 lit | B) 6 lit |

C) 16 lit | D) 12 lit |

Explanation:

Given ratio of initial mixture of milk and water in Q = 5 : 3

Let the initial quantity of mixture in vessel Q = 8x

Let quantity of Milk = 5x and

Let quantity of water = 3x

According to the question,

$\frac{\mathbf{5}\mathbf{x}\mathbf{}\mathbf{+}\mathbf{}\mathbf{10}\mathbf{}\mathbf{x}\mathbf{}{\displaystyle \frac{\mathbf{3}}{\mathbf{5}}}}{\mathbf{3}\mathbf{x}\mathbf{}\mathbf{+}\mathbf{}\mathbf{10}\mathbf{}\mathbf{x}\mathbf{}{\displaystyle \frac{\mathbf{2}}{\mathbf{5}}}\mathbf{}}\mathbf{}\mathbf{=}\mathbf{}\frac{\mathbf{8}}{\mathbf{5}}$

=> 25x + 30 = 24x + 32

=> x = 2

Required Initial quantity of milk = 5x = 5 x 2 = 10 lit.

A) Rs. 1600 | B) Rs. 1700 |

C) Rs. 1800 | D) Rs. 1900 |

Explanation:

Let the salaries of Maneela and Shanthi one year before be **M1, S1** & now be **M2, S2** respectively.

Then, from the given data,

M1/S1 = 3/4 .....(1)

M1/M2 = 4/5 .....(2)

S1/S2 = 2/3 .....(3)

and M2 + S2 = 4160 .....(4)

Solving all these eqtns, we get M2 = Rs. 1600.

A) 444 | B) 344 |

C) 244 | D) 144 |

Explanation:

Given ratio of pens and pencils = 3 :2

Number of Pens = 3x

Number of Pencils = 2x

Average number of pencils & Pens = $\frac{\mathbf{3}\mathbf{x}\mathbf{}\mathbf{+}\mathbf{}\mathbf{2}\mathbf{x}}{\mathbf{2}}\mathbf{}\mathbf{=}$ 180

5x = 360

=> x = 72

Hence, the number of pencils **= 2x = 72 x 2 = 144.**

A) 17 | B) 30 |

C) 26 | D) 32 |

Explanation:

$3\phantom{\rule{0ex}{0ex}}{3}^{2}+3=12\phantom{\rule{0ex}{0ex}}5\phantom{\rule{0ex}{0ex}}{\mathbf{5}}^{\mathbf{2}}\mathbf{}\mathbf{+}\mathbf{}\mathbf{5}\mathbf{}\mathbf{=}\mathbf{}\mathbf{30}$