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Q:

$142^{2} \div \sqrt{1260.25} = ?$

A) 586	B) 578
C) 568	D) 566

Answer & Explanation Answer: C) 568

Explanation:

$142 x 142 x \frac{1}{\sqrt{1260.25}}$

=> $142 x 142 x \frac{1}{35.5} = 568$

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Q:

$\frac{23 x 12 + 49 x 15}{31^{2} + 50} = ?$

A) 0.5	B) 1
C) 2	D) 3

Answer & Explanation Answer: B) 1

Explanation:

$\frac{276 + 35}{961 + 50} = \frac{1011}{1011} = 1$

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Q:

$2660 o f \frac{1}{7} o f \frac{1}{2} o f \frac{1}{9.5} o f \frac{1}{2} = ?$

A) 1	B) 10
C) 0.1	D) 100

Answer & Explanation Answer: B) 10

Explanation:

$\frac{1}{7} x \frac{1}{2} x \frac{1}{9.5} x \frac{1}{2} x 2660 = \frac{2660}{266} = 10$

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Q:

The average age of a group of 10 students is 15 years. When 5 more students join the group, the average age increase by 1 year. The average age of the new students is?

Answer

Total age of 10 students = 150 years

Total age of 15 students = 240 years

Total age of 5 new students = 240 - 150 = 90 years

$\inline \therefore$ Average age of 5 new students = $\frac{90}{5}$ = 18 years

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Subject: Problems on Ages

Q:

The Age of Ashok , Deepak and Ramu are in the proportion of 3:5:6. If the difference between the ages of Deepak and Ramu is 5 years . what is Ashok's age in years?

Answer

Suppose the ages of Ashok, Deepak and Ramu are 3x, 5x and 6x years respectively.

$6x-5x=5\: \: \Rightarrow x=5$

Hence , Ashok's age = $3x$ = $3\times 5$ = 15 years

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Subject: Problems on Ages

Q:

One year ago the ratio between Mohan and Ashok's age was 4:3 after one yerar the rato of their ages will be 5:4 . what is the sunm of their present ages in years.

Answer

Let their ages one year ago be 4x and 3x years

$\Rightarrow \frac{4x+2}{3x+2}=\frac{5}{4}\Rightarrow 4(4x+2)=5(3x+2)$