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Q:

The sum of the number of boys and girls in a school is 150. if the number of boys is x, then the number of girls becomes x% of the total number of students. The number of boys is :

A) 60	B) 70
C) 80	D) 90

Answer & Explanation Answer: A) 60

Explanation:

We have : x + (x% of 150 )= 150

=> x+(x/100)*150] = 150

=> $\frac{5}{2} x = 150$

=> x = (150*2)/5 = 60

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Q:

If 20% of a = b, then b% of 20 is the same as :

A) 4% of a	B) 6% of a
C) 8% of a	D) 10% of a

Answer & Explanation Answer: A) 4% of a

Explanation:

20% of a = b

=> (20/100) * a = b

b% of 20 =(b/100) x 20 = [(20a/100) / 100] x 20= 4a/100 = 4% of a.

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Q:

The value of a machine depreciates at the rate of 10% every year. It was purchased 3 years ago. If its present value is Rs. 8748, its purchase price was :

A) 10000	B) 12000
C) 14000	D) 16000

Answer & Explanation Answer: B) 12000

Explanation:

Purchase price = $R s . [\frac{8748}{{^{(1 - \frac{10}{100})}}^{3}}]$ = Rs. [8748 * (10/9) * (10/9 )* (10/9)] = Rs.12000

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Q:

The diference of two numbers is 20% of the larger number, if the smaller number is 20, then the larger number is :

A) 15	B) 25
C) 35	D) 45

Answer & Explanation Answer: B) 25

Explanation:

Let the large number be x.

Then x - 20 = 20x/100

=> x - x/5 = 20 => x = 25.

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Q:

If 75% of a number is added to 75, then the result is the number itself. The number is :

A) 100	B) 200
C) 300	D) 400

Answer & Explanation Answer: C) 300

Explanation:

Let the number be x, Then

75% of x + 75 = x

=> x - 75x/100 =75

=> x = 300 .

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Q:

A student has to obtain 33% of the total marks to pass. He got 125 marks and failed by 40 marks. The maximum marks are :

A) 500	B) 600
C) 800	D) 1000

Answer & Explanation Answer: A) 500

Explanation:

Given that the student got 125 marks and still he failed by 40 marks

=> The minimum pass mark = 125 + 40 = 165

Given that minimum pass mark = 33% of the total mark

=> total mark =33/100 =165

=> total mark = 16500/33 = 500

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Q:

In an examination, 34% of the students failed in Mathematics and 42% faiied in English. If 20% of the students failed in both the subjects, then the percentage of students who passed in both the subjects was :

A) 34 %	B) 44 %
C) 54 %	D) 64 %

Answer & Explanation Answer: B) 44 %

Explanation:

n (A) = 34, n (B) = 42, n (A ∩ B) = 20.

So, n (A U B) = n (A) + n(B) - n(A ∩B) = 34 + 42 - 20 = 56.

Percentage failed in either or both the subjects = 56.

Hence, percentage passed = (100 - 66)% = 44%.

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Filed Under: Percentage

Q:

270 candidates appeared for an examination, of which 252 passed. The pass percentage is :

A) (91 + 1/3)%	B) (93 + 1/3 )%
C) (97 + 1/3 )%	D) (98 + 1/3) %

Answer & Explanation Answer: B) (93 + 1/3 )%

Explanation:

Pass percentage =[(252/270)*100] % =280/3 % = $93 \frac{1}{3}$ 9 %

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