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Q:

There are several peacocks and deers in a cage (with no other types of animals). There are 72 heads and 200 feet inside the cage. How many peacocks are there, and how many deers ?

A) 42 & 24	B) 38 & 26
C) 36 & 24	D) 44 & 28

Answer & Explanation Answer: D) 44 & 28

Explanation:

Let
x = peacocks
y = deers

2x + 4y = 200
x + y = 72
y = 72 - x
2x + 288 - 4x = 200
x = 44 peacocks
y = 28 deers

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Filed Under: Numbers
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Q:

P, Q, R, S, T, U, V and W are sitting round the circle and are facing the centre:
P is second to the right of T who is the neighbour of R and V.
S is not the neighbour of P.
V is the neighbour of U.
Q is not between S and W. W is not between U and S.

Then Who is sitting opposite to U ?

A) Q	B) P
C) R	D) W

Answer & Explanation Answer: B) P

Explanation:

From the given information, the sitting arrangement can be

P-Q-W-S-U-V-T-R i.e. in circular as

p11487572312.jpg image

From the above figure it is clear that opposite to U is P.

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Filed Under: Number, Ranking and Time Sequence Test
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Q:

On a ruler's tombstone, it is said that one sixth of his life was spent in childhood and one twelfth as a teenager. One seventh of his life passed between the time he became an adult and the time he married; five years later, his son was born. Alas, the son died four years before he did. He lived to be twice as old as his son did. How old did the ruler live to be ?

A) 84 years	B) 72 years
C) 82 years	D) 64 years

Answer & Explanation Answer: A) 84 years

Explanation:

Let the age of ruler is x so that of son = x/2 (given)
Now according to the given condition
(x/6) + (x/12) + (x/7) + 5 + (x/2) + 4 = x
=> x = 84

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Filed Under: Problems on Ages
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Q:

M and N have children A and B.
F is spouse of B.
D is child of F.
P is son in law of N.
K is kid of P.

Who is male chiled of M and N ?

A) B	B) A
C) None	D) Can't be determined

Answer & Explanation Answer: A) B

Explanation:

Spouse means a person's partner in marriage, it can be male or female.
But given F is spouse of B
And P is Son in law of N
Relation between F and B
Relation between P and A only
and p is male So, A must be female
=> B is male child.

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Filed Under: Logic
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Q:

A secret can be told to only 3 persons in 3 minutes. Each person in turn tells 3 other persons in the next 3 minutes and the processes continues accordingly. In 30 minutes how many persons can be told this secret in this way ?

A) 88572	B) 77854
C) 99584	D) 55654

Answer & Explanation Answer: A) 88572

Explanation:

Given a secret is told to 3 persons in 3 minutes.
And if the process continues with each person saying 3 other persons,
In 30 minutes => the rocess for 10 times because each person time is 3 minutes.
Required number of persons = $3 + 3^{2} + 3^{3} + . . . . + 3^{9} + 3^{10}$

Now it forms a geometric progression,

Sum to n terms is $S = \frac{a (r^{n} - 1)}{r - 1}$

Here a = 3, r = 3

=> 59048 x 3 /2

= 88572.

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Filed Under: Simplification
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Q:

A company requires 12,100 strength. Present employees are 400 ladies and 6400 gents. To reach the target how many ladies required to maintain the same ratio ?

A) 400	B) 600
C) 900	D) 700

Answer & Explanation Answer: C) 900

Explanation:

6,400 gents, 2400 ladies in that company.
So total 8,800employees.
for 8,800 employees, we want 2400 ladies.
for 12,100employees we want how many ladies ?
=> (12,100/8,800) x 2400 = 3300.
So we want 3300 - 2400 = 900 more ladies.

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Filed Under: Ratios and Proportions
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Q:

On a school’s Annual day sweets were to be equally distributed amongst 112 children. But on that particular day, 32 children were absent. Thus the remaining children got 6 extra sweets. How many sweets was each child originally supposed to get ?

A) 14	B) 16
C) 12	D) 15

Answer & Explanation Answer: D) 15

Explanation:

Let 'K' be the total number of sweets.
Given total number of students = 112
If sweets are distributed among 112 children,
Let number of sweets each student gets = 'L'

=> K/112 = L ....(1)
But on that day students absent = 32 => remaining = 112 - 32 = 80
Then, each student gets '6' sweets extra.

=> K/80 = L + 6 ....(2)
from (1) K = 112L substitute in (2), we get
112L = 80L + 480
32L = 480
L = 15

Therefore, 15 sweets were each student originally supposed to get.

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Filed Under: Average
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Q:

A supplier supplies cartridges to a news paper publishing house. He earns a profit of 25% by selling cartridges for Rs. 1540. Find the cost price of the Cartridges ?

A) Rs. 1100	B) Rs. 1793.4
C) Rs. 1440	D) Rs. 1232

Answer & Explanation Answer: D) Rs. 1232

Explanation:

Let Cost Price(C.P) = P
gain% = {(S.P-C.P)/C.P} x 100
25 = {(1540-P)/P} x 100
25/100 = (1540-P)/P
=> P = 4(1540)-4P
=> 5P = 4(1540)
=> P = 1232
So, Cost Price = Rs. 1232

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Filed Under: Profit and Loss
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