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Q:

In a 300 m race, A beats B by 22.5 m or 6 seconds. B's time over the course is:

A) 86 sec	B) 80 sec
C) 76 sec	D) None of these

Answer & Explanation Answer: B) 80 sec

Explanation:

B runs 45/2mts in 6 sec

B covers 300m in (6*2/45*300)sec =80 sec

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Filed Under: Races and Games

Q:

In a 200 metres race A beats B by 35 m or 7 seconds. A's time over the course is:

A) 40 sec	B) 47 sec
C) 33 sec	D) None of these

Answer & Explanation Answer: C) 33 sec

Explanation:

B runs 35 m in 7 sec.

B covers 200 m in (7/35*200) = 40sec

B's time over the course = 40 sec.

A's time over the course (40 - 7) sec = 33 sec.

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Filed Under: Races and Games

Q:

What is the difference between the compound interests on Rs. 5000 for $1 \frac{1}{2}$ years at 4% per annum compounded yearly and half-yearly?

A) Rs.3.06	B) Rs.2.04
C) Rs.3.65	D) Rs.5.40

Answer & Explanation Answer: B) Rs.2.04

Explanation:

C.I. when interest compounded yearly

$R s . [5000 * (1 + \frac{4}{100}) * (1 + \frac{\frac{1}{2} * 4}{100})]$

$R s . [5000 * \frac{26}{25} * \frac{51}{50}]$

=Rs.5034

C.I. when interest iscompounded half-yearly

$R s . [5000 * {(1 + \frac{2}{100})}^{3}]$

= Rs. 5306.04

Difference = Rs. (5306.04 - 5304) = Rs. 2.04

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Filed Under: Compound Interest
Exam Prep: Bank Exams
Job Role: Bank PO

Q:

What will be the compound interest on a sum of Rs.25,000 after 3 years at the rate of 12 p.c.p.a?

A) Rs.10123.20	B) Rs.12100
C) Rs.12552	D) Rs.12665

Answer & Explanation Answer: A) Rs.10123.20

Explanation:

Amount

= Rs.(25000x(1+12/100)³

= Rs.(25000x28/25x28/25x28/25)

= Rs. 35123.20.

C.I = Rs(35123.20 -25000)

= Rs.10123.20

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Filed Under: Compound Interest
Exam Prep: GRE

Q:

If the simple interest on a sum of money at 5% per annum for 3 years is Rs. 1200, find the compound interest on the same sum for the same period at the same rate.

A) Rs.1251	B) Rs.1261
C) Rs.1271	D) Rs,1281

Answer & Explanation Answer: B) Rs.1261

Explanation:

Clearly, Rate = 5% p.a .,

Time = 3 years

S.I =Rs.1200.

So,Principal

=Rs.(100 x 1200/3x5)

=Rs.8000.

Amount

=Rs.[8000 x (1+5/100)³]

=Rs(8000x21/20x21/20x21/20)

= Rs.9261

C.I

=Rs.(9261-8000)

=Rs.1261.

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Filed Under: Compound Interest
Exam Prep: Bank Exams
Job Role: Bank PO

Q:

If the simple interest on a sum of money for 2 years at 5% per annum is Rs. 50, what is the compound interest on the same at the same rate and for the same time?

A) Rs.51.25	B) Rs.52
C) Rs.53	D) Rs.54

Answer & Explanation Answer: A) Rs.51.25

Explanation:

Sum =Rs.(50 x 100/2x5)

= Rs. 500.

Amount

=[Rs.500x(1+5/100)²]

=Rs(500x21/20x21/20).

=Rs. 551.25

C.I

= Rs. (551.25 - 500)

= Rs. 51.25

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Filed Under: Compound Interest
Exam Prep: Bank Exams
Job Role: Bank PO

Q:

Output of the Program :

main()

{

int i = 1;

while (i <= 5)

{

printf( "%d", i );

if (i > 2) goto here;

i++;

}

fun()

{

here : printf( "PP" );

}

A) 1	B) 2
C) Compilation error	D) Exception occurs

Answer & Explanation Answer: C) Compilation error

Explanation:

Compiler error: Undefined label 'here' in function main

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Filed Under: Programming

Q:

Two electric bulbs marked 25W – 220V and 100W – 220V are connected in series to a 440Vsupply. Which of the bulbs will fuse?

A) 25 W	B) Both
C) 100 W	D) Neither

Answer & Explanation Answer: A) 25 W

Explanation:

Resistances of both the bulbs are

R1=V^2/P1 = 220^2/25

R2 = V^2/P2 = 220^2/100

Hence $R 1 g t; R 2$

When connected in series, the voltages divide in them in the ratio of their resistances. The voltage of 440 V devides in such a way that voltage across 25 w bulb will be more than 220 V. Hence 25 w bulb will fuse.

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Filed Under: Physics
Exam Prep: AIEEE

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