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Q:

The market price of an article was 40% more than its cost price. Rana was going to sell it at market price to a customer, but he showed Rana some defects in the article, due to which Rana gave him a discount of 28.57%. Next day he came again and showed Rana some more defects, hence he gave him another discount that was equal to 12.5% of the cost price. What was the approximate profit/loss to Rana ?

A) Loss of 12.5% B) Profit of 12.5%
C) Loss of 24.5% D) Profit of 22.5%
 
Answer & Explanation Answer: A) Loss of 12.5%

Explanation:

Let the cost price be Rs. 100
Then, market price is Rs. 140
Now, the first discount is of 28.57% Rs.140 =~ Rs. 40
Hence, its selling price = 140 - 40 = Rs. 100
Now since Rana is selling at cost price, any further discount will be equal to loss percentage.
The next dicount of 12.5% will be the loss percentage to Rana.

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Q:

In a certain code DOWN is written as '5@9#' and NAME is written as '#6%3'. How is MODE written in that code ?

A) 6@53 B) %@53
C) 53%# D) %#35
 
Answer & Explanation Answer: B) %@53

Explanation:

From the given information :

D O W N A M E == 5 @ 9 # 6 % 3
MODE = %@53

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Q:

Vishal invested 10% more than Trishul. Trishul invested 10% less than Raghu. If the total sum of their investments is Rs. 5780, how much amount did Raghu invest ?

A) Rs.2010 B) Rs.2200
C) Rs.2000 D) Rs.2100
 
Answer & Explanation Answer: C) Rs.2000

Explanation:

Let money invested by Raghu = Rs. x
Money invested by Trishul = 9/10 x = 0.9x
Money invested by Vishal = 9/10x * 110/100 = 0.99x
Also, x+0.9x+0.99x = 5780
= x= 5780/2.89 = 2000

Therefore, amount invested by Raghu is Rs. 2000.

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Q:

'A' sold an article to 'B' at a profit of 20%. 'B' sold the same article to 'C' at a loss of 25% and 'C' sold the same article to 'D' at a profit of 40%. If 'D' paid Rs 252 for the article, then find how much did 'A' pay for it?

A) Rs.196 B) Rs.210
C) Rs.200 D) Rs.235
 
Answer & Explanation Answer: C) Rs.200

Explanation:

Let the article costs 'X' to A
Cost price of B = 1.2X
Cost price of C = 0.75(1.2X) = 0.9X
Cost price of D = 1.4(0.9X) = 1.26X = 252
Amount paid by A for the article = Rs. 200.

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Q:

How many meaningful English words can be formed with the letters LGEU using each letter only once in each word ?

A) Zero B) One
C) Two D) Four
 
Answer & Explanation Answer: B) One

Explanation:

'GLUE' is the only meaningful word that can be formed using the letters given.

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Q:

In a certain code language, 'how can you go' is written as 'ja da ka pa', 'can you come here' is written as 'na ka sa ja' and 'cone and go' is written as 'ra pa sa'. How is 'here' written in that code ?

A) na B) ja
C) sa D) None
 
Answer & Explanation Answer: A) na

Explanation:

From the given information :

how can you go = ja da ka pa....(1)
can you come here = na ka sa ja...(2)
come and go = ra pa sa....(3)
from (1)&(2), can you = ja ka...(4)
from (2)&(3), come = sa...(5)
Using (4)&(5) in (2), we get here = na.

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Q:

What should come next in the following letter series based on English alphabet ?
CEA JLH QSO ?

A) WYU B) UXW
C) WXV D) XZV
 
Answer & Explanation Answer: D) XZV

Explanation:

In the given series, each letter moves seven letters forward to obtain the next.
So, XZV replaces ? in the series.

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Q:

Without any stoppage, a person travels a certain distance at an average speed of 42 km/h, and with stoppages he covers the same distance at an average speed of 28 km/h. How many minutes per hour does he stop?

A) 15 minutes B) 20 minutes
C) 18 minutes D) 22 minutes
 
Answer & Explanation Answer: B) 20 minutes

Explanation:

Let the total distance to be covered is 84 kms.
Time taken to cover the distance without stoppage = 84/42 hrs = 2 hrs
Time taken to cover the distance with stoppage = 84/28 = 3 hrs.
Thus, he takes 60 minutes to cover the same distance with stoppage.
Therefore, in 1 hour he stops for 20 minutes.

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