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Q:

Trichloroacetaldehyde was subject to Cannizzaro's reaction by using NaOH. The mixture of the products contains sodium trichloroacetate and another compound. The other compound is :

A) Chloroform	B) 2, 2, 2-Trichloroethanol
C) Trichloromethanol	D) 2, 2, 2-Trichloropropanol

Answer & Explanation Answer: B) 2, 2, 2-Trichloroethanol

Explanation:

$\begin{matrix} C l \\ | \\ C l & - & C & - & C H O \\ | \\ C l \end{matrix}$ $\to_{C a n n i z z a r o' s R e a c t i o n}^{N a O H}$ $\begin{matrix} C l \\ | \\ C l & - & C & - & C O O N a \\ | \\ C l \end{matrix}$ $+$ $\begin{matrix} C l \\ | \\ C l & - & C & - & C H_{2} \\ | 2 & 1 \\ C l \end{matrix}$ $- O H$

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Filed Under: Chemistry
Exam Prep: AIEEE

Q:

In 1926, Which of the following universties was founded by Madan Mohan Malaviya alond with Anne Besant ?

A) Punjab university	B) Delhi University
C) Benaras Hindu University	D) University of Madras

Answer & Explanation Answer: C) Benaras Hindu University

Explanation:

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Filed Under: General Awareness

Q:

Which of the following was banned by Supreme Court of India in 2014 ?

A) Kick Boxing	B) Malla Yuddam
C) Kalari Payattu	D) Jallikattu

Answer & Explanation Answer: D) Jallikattu

Explanation:

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Filed Under: Indian Culture

Q:

Driest areas of India which lie Rajastan have an average annual rainfall of _____

A) 10 cm	B) 1cm
C) Between 1 cm to 10 cm	D) Less than 1cm

Answer & Explanation Answer: D) Less than 1cm

Explanation:

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Filed Under: Indian Geography

Q:

A and B start a business, with A investing the total capital of Rs.50000, on the condition that B pays A interest @ 10% per annum on his half of the capital. A is a working partner and receives Rs.1500 per month from the total profit and any profit remaining is equally shared by both of them. At the end of the year, it was found that the income of A is twice that of B. Find the total profit for the year?

A) Rs. 39000	B) Rs. 49000
C) Rs. 59000	D) Rs. 69000

Answer & Explanation Answer: C) Rs. 59000

Explanation:

Interest received by A from B = 10% of half of Rs.50000 = 10% of Rs. 25000 = Rs.2500.

Amount received by A per annum for being a working partner = 1500 x 12 = Rs.18000

Let 'P' be the part of the remaining profit that A receives as his share.

So,total income of A = (Rs.2500 + Rs.18000 + Rs. P )

Total income of B = only his share from the remaining profit = 'P', as A and B share the remaining profit equally.

We know that income of A = Twice the income of B

So, (2500 + 18000 + P ) = 2(P)

P = 20500

Thus, the total profit = 2P + Rs.18000

= 2(20500) + 18000 = Rs.59000.

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Filed Under: Partnership

Q:

Explain in your words about Channel of communication, Skipper and Sundry Services.

Answer

Channel of communication : It is a floe of communication within a department.

Skipper : This term is used for the status of a room, which indicates that a guest has left the hotel room without arranging to settle his or her account.

Sundry Services :These are the extra services, which are provided to the guests. For e.g. message, handling of guests.

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Subject: Hospitality

Q:

What is Materials Requirement Planning?

Answer

A given quantity of finished goods requires a given quantity of raw materials and components to make them. Materials requirement planning systems to make them. Materials requirements planning systems are computerized tools that manage when materials must be ordered to supply production at a later date. MRP is effective when output quantities are known.Small business owners are often their own MRP systems,storing the information needed to supply prodution in their knowledge and experience. Activities such as computer tracking inventory and forecasting demand are MRP activities.

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Subject: Manufacturing

Q:

A certain sum is to be divided between A and B so that after 5 years the amount received by A is equal to the amount received by B after 7 years. The rate of interest is 10%, interest compounded annually. Find the ratio of amounts invested by them.

please solve this

Answer

Let the sum(principal) received by A and B are x and y.

(1+r) = $1+\frac{1}{10}$ = $\frac{11}{10}$

Then, $\frac{x}{y}=\left ( \frac{11}{10} \right )^{7-5}$ = $\left ( \frac{11}{10} \right )^2 =\frac{121}{100}$

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