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Q:

Four persons can cross a bridge in 3,7,13,17 minutes.Only two can cross at a time.Find the minimum time taken by the four to cross the bridge ?

A) 17 minutes	B) 20 minutes
C) 34 minutes	D) 12 minutes

Answer & Explanation Answer: B) 20 minutes

Explanation:

First send 17 and 7. After 7 minutes, 7 is at finish and 17 needs 10 more minutes to complete his travel. now send 13. After 10 minutes 17 reaches finish and 13 needs 3 more minutes to complete. now send 3. both 3 and 13 reach destination at the same time after 3 minutes. hence the time taken is 7+10+3=20 minutes.

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Filed Under: Logic
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Q:

Five farmers have 7,9,11,13 & 14 apple trees respectively in their orchards. Last year each of them discovered that every tree in their own orchard yields exactly the same number of apples. Further, if the 3rd farmer gives one apple to the 1st and the 5th gives 3 to each of the 2nd & d 4th, they would all exactly have the same number of apples, what were the yields per tree in the orchards of the 3rd & 4th farmers ?

A) 17 & 9	B) 9 & 11
C) 9 & 9	D) 11 & 9

Answer & Explanation Answer: D) 11 & 9

Explanation:

Let the number of apples in each tree of the 5 farmers be a, b, c, d,e respectively. Therefore total no of apples are 7a, 9b, 11c, 13d and 14e respectively.

Given,
7a+1 = 9b+3 = 11c-1 = 13d+3 = 14e-6 = x

9b+3 = 13d+3
===> 9b = 13d
so take b = 13 and d = 9

9b+3 = 9*13+3 = 120
ie, x=120

substituting
7a+1 = 120
7a = 119
a = 17

11c-1 = 120
11c = 121
c=11

14e-6 = 120
14e = 126
e = 9

Yields per tree in the orchards of d 3rd & 4th farmers= 11,9

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Filed Under: Arithmetical Reasoning
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Q:

Find the next number in te given series ?

5, 25, 61, 113, ...

A) 142	B) 181
C) 156	D) 179

Answer & Explanation Answer: B) 181

Explanation:

Here the series follow the rule that

$1^{2} + 2^{2} = 5$

$3^{2} + 4^{2} = 25$

$5^{2} + 6^{2} = 61$

$7^{2} + 8^{2} = 113$

SO NEXT IS, $9^{2} + 10^{2} = 181$

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Filed Under: Odd Man Out
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Q:

If 6 engines consume 24 metric tonnes of coal, when each is working 8 hours day, how much coal will be required for 9 engines, each running 13hours a day, it being given that 2 engines of former type consume as much as 3 engines of latter type ?

A) 45 metric tonnes	B) 47 metric tonnes
C) 55 metric tonnes	D) 34 metric tonnes

Answer & Explanation Answer: A) 45 metric tonnes

Explanation:

2 engines of former type for one hour consumes (2 x 24)/(6 x8) = 1 metric ton

i.e. 3 engines of latter type consumes 1 ton for one hour

Hence 9 engines consumes 3 tons for one hour

For 15 hours it is 15 x 3 = 45 metric tonnes.

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Filed Under: Time and Work
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Q:

By investing Rs. 1620 in 8% stock, Michael earns Rs. 135. The stock is then quoted at ?

A) Rs. 145	B) Rs. 245.1
C) Rs. 96	D) Rs. 75

Answer & Explanation Answer: C) Rs. 96

Explanation:

Michel earns Rs. 135 by investing Rs. 1620
To earn Rs. 8 how much he have to invest...?

= (8 x 1620)/135 = Rs. 96

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Filed Under: Stocks and Shares
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Q:

If N is the greatest number that will divide 1305, 4665 and 6905, leaving the same remainder in each case. What is the sum of the digits of N ?

A) 6	B) 8
C) 4	D) 9

Answer & Explanation Answer: C) 4

Explanation:

N = H.C.F. of (4665 - 1305), (6905 - 4665) and (6905 - 1305)

= H.C.F. of 3360, 2240 and 5600 = 1120.

Sum of digits in N = ( 1 + 1 + 2 + 0 ) = 4

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Filed Under: HCF and LCM
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Q:

The ratio of present ages of Hema and Chinnu is 13:17. Four years ago the ratio of their ages was 11:15. What will be the ratio of their ages six years hence ?

A) 3 : 7	B) 7 : 9
C) 4 : 5	D) 1 : 3

Answer & Explanation Answer: C) 4 : 5

Explanation:

Let their present ages be 13x and 17x.
Then, 13x-4/17x-4 = 11/15.
Solving this, we get x = 2.
Required ratio = 13x2 + 6/17x2 + 6 = 32/40 = 4/5.

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Filed Under: Problems on Ages
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Q:

The sum of 3rd and 15th elements of an arithmetic progression is equal to the sum of 6th, 11th and 13th elements of the same progression. Then which element of the series should necessarily be equal to zero ?

A) 14th element	B) 9th element
C) 12th element	D) 7th element

Answer & Explanation Answer: C) 12th element

Explanation:

If we consider the third term to be ‘x”
The 15th term will be (x + 12d)
6th term will be (x + 3d)
11th term will be (x + 8d) and
13th term will be (x + 10d).
Thus, as per the given condition, 2x + 12d = 3x + 21d.Or x + 9d = 0.
x + 9d will be the 12th term.

Thus, 12th term of the A.P will be zero.

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Filed Under: Chain Rule
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