Scores of individuals :

Dhoni= 80,30,10,10,1
Raina=100,25,3,2,1
Kholi=85,20,15,10,1
Shikhar=90,20,15,3,3

Above combination satisfies all conditions given in the question.

Answer 1) Raina

Answer 2) Kohli and Shikhar

Answer 3) Dhoni

Lets say shyam sells at 100,

Since Ram sells 25% cheaper than Shyam,

Therefor Ram sells at less than 25% of100 or 75 rs.

Ram sells 25% dearer than Bram or 125% of Ram =100% of Bram or

125% of x (say x price of bram )=75rs.
or 100% of x =60rs.
hence price of bram is 60rs.

now Bram's good is cheaper than Shyam's as (100-60)x100/100% or 40%.

Hence Brams Good is 40% cheaper than that of Shyam's good.

Plug and Play is a technology wherein hardware components that are installed on PCs using Microsoft operating system are immediately recognized and made usable. This means that the drivers necessary to make it work are already available on the operating system package.

Standard modules contain variables, procedures and functions that are accessible anywhere within the project. A class module contains properties and events, and is made accessible only by objects that were created as an instance of that class.

Since level of water increased in cylinder by height 4. 

This is because of the rectangular block .

Therefore , area of rectangular block immersed in water is 

= 227×6×6×4  

Thats why portion of block immersed in water is 

= (22/7 * 36 * 4) / total vol. of rectangle 

= (22/7 * 36 * 4)/ (7*5*6) 

= (22/7 * 24)/ 35.

Let y be the total number of loaves
a be the remaining loaves after 1st thief
b be the remaining loaves after 2nd thief
and c, d..so on after 3 and 4 th
e = 0 be the remaining loaves after 5th thief

a = y - (y/2 + 1/2)
= y/2 - 1/2

b = a - (a/2 + 1/2)
= a/2 - 1/2

c = b - (b/2 + 1/2)
= b/2 - 1/2

d = c - (c/2 + 1/2)
= c/2 - 1/2

e = d - (d/2 + 1/2)
= d/2 - 1/2
we know that, e = 0,
thus by substitution, we get
d = 1
c = 3
b = 7
a = 15
y = 31
Therefore total number of bread loaves in bakery was 31.

Out of 4 fruits, any 3 are chosen by 4 families.So the combinations are
Apple - A Cherries - C Banana - B Grapes - G
1) ACB
2) ACG
3) BCG
4) GAB

By 2nd condition, Miller family uses either i)ACB or ii)ACG
Now we have Robin, Mandy and Miller who uses apples (ACB,ACG,GAB)
while Miller and Mandy both uses A and C. That leaves GAB for Robin.

By 3rd condition Flure uses either C or G. So if we leave out the terms containing both C and G, we are left with ACB and GAB

Now, for the time being let's suppose Robin is not a Flure.
So ACB is taken by Flure.

So ACG has to be Miller and that leaves BCG to be Clark. So we get Robin - Jacob(GAB).

By 4th and 2nd conditions Erica and Mandy belong to the first two. That leaves Stacy - Clark(BCG).

By 2nd condition Mandy is not a Miller, so we get Mandy - Flure(ACB) and that leaves Erica - Miller(ACG).