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Q:

Den Bosch and Eastbourne are two famous cities 300 km apart. Maradona starts from Den Bosch at 8:24 am . An hour later pele starts from Den Bosch. After travelling for 1 hour , Pele reaches Nottingham that Maradona had passed 40 minutes earlier. Nottingham falls on the way from Den Bosch to Eastbourne. If pele and Maradona just reaches Eastbourne at the same time, what are thespeeds of the Maradona and Pele Respectively?

A) 100 km/h , 125 km/h	B) 60 km/h , 80 km/h
C) 60 km/h , 75 km/h	D) 75 km/h , 100 km/h

Answer & Explanation Answer: D) 75 km/h , 100 km/h

Explanation:

Let Pele x km in 1 hour. so Maradona takes (2h-40min)=1 h 20 min to cover x km. Let speed of Maradona and Pele be M and P respectively than

x =M x (4/3) and x= P x 1

=> M/P = 3/4

Again $\frac{300}{M} = \frac{300}{P} = 1$

$\Rightarrow \frac{300}{3 k} - \frac{300}{4 k} = 1$

=> k= 25

M= 3k = 75 km/h and P= 4k = 100 km/h

( Through options it is very easy to solve)

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Filed Under: Time and Distance

Q:

A motor boat takes 12 hours to go downstream and it takes 24 hours to return the same distance. what is the time taken by boat in still water?

A) 15 h	B) 16 h
C) 8 h	D) 20 h

Answer & Explanation Answer: B) 16 h

Explanation:

If t1 and t2 are the upstream and down stream times. Then time taken in still water is given by

$\frac{2 \times t 1 \times t 2}{t 1 + t 2} = \frac{2 \times 12 \times 24}{36} = 16 h$

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Filed Under: Boats and Streams

Q:

Two horses start trotting towards each other, one from A to B and another from B to A. They cross each other after one hour and the first horse reaches B, 5/6 hour before the second horse reaches A. If the distance between A and B is 50 km. what is the speed of the slower horse?

A) 30 km/h	B) 15 km/h
C) 25 km/h	D) 20 km/h

Answer & Explanation Answer: D) 20 km/h

Explanation:

If the speed of the faster horse be $f_{s}$ and that of slower horse be $s_{s}$ then

$f_{s} + s_{s} = \frac{50}{1} = 50$

and $\frac{50}{s_{s}} - \frac{50}{f_{s}} = \frac{5}{6}$

Now, you can go through options.

The speed of slower horse is 20km/h

Since, 20+30=50

and $\frac{50}{20} - \frac{50}{30} = \frac{5}{6}$

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Q:

A train overtakes two girls who are walking in the opposite direction in which the train is going at the rate of 3 km/h and 6km/h and passes them completely in 36 seconds and 30 seconds respectively. The length of the train is:

A) 120m	B) 150m
C) 125m	D) None of these

Answer & Explanation Answer: B) 150m

Explanation:

Let the length of the train e x meter, and let the speed of train be y km/h, then

$x = (y + 3) \times \frac{5}{18} \times 36$ --------(1) and

$x = (y + 6) \times \frac{5}{18} \times 30$ ---------(2)

From eq (1) and (2), we get

y = 12 km/h

Therefore, $x = (y + 3) \times \frac{5}{18} \times 36$ => x= 150 m

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Q:

A Person X started at 3 hours earlier at 40km/h from a place P, then another person Y followed him at 60km/h. Started his journey at 3 O'clock, afternoon. What is the diference in time when X was30 km ahead of Y and when Y was 30 km ahead of X?

A) 2h	B) 3h
C) 3.5h	D) 4.25h

Answer & Explanation Answer: B) 3h

Explanation:

Time ( when X was 30 km ahead of Y) = (120-30)/20 =4.5h

Time ( when Y was 30 km ahead of X) = (120+30)/20 = 7.5 h

Thus, required difference in time = 3h

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Q:

Arjun and Bhishma are running on a circular track of length 600m. Speed of Arjun is 30 m/s and that of Bhishma is 20 m/s .They start fro the same point at the same time in the same direction. When will they meet again for the first time?

Answer

Sol : $Time = \frac{Circumference}{Relative Speed} = \frac{600}{10} = 60 \sec .$

Actually Arjun has to make a lead of 600 m, because when Arjun will be 600m ahead of Bhishma, they will be together again as a person when completes the total length it starts retracing he same path and thus Arjun and Bhishma can be together again.

Since , they make a difference of 10 m in 1 second. so, he will create 600m difference in 60 second.

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Subject: Time and Distance Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Bank Clerk , Bank PO

Q:

In a one km race A gives B a start of 100m and in a one km race B gives a start of 80 m to C. In a 1 km race who will win and by how much distance from the worst performer between two losers?

Answer

Ratio of speeds of A:B = 1000:900 = 100:90

Ratio of speeds of B:C = 1000:920 = 100:92

Therefore, when A moves 1000m , B moves 900 m and when B moves 900m, C moves 828m

Thus, $\begin{matrix} \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; 828m\; \; \;\; \; 900m\;\; \; \; \; 1000m\\ A...............|........|..........|\\ \; \; \; \;\; \; \; \; \; \; \; \; \; \; \; \; \; C\; \; \; \; \; \; \; \; B\; \; \; \; \; \; \; \; \; A \end{matrix}$

Since , C moves 8 % less than B in the same time . Thus, C is the worst performer and A will win by him by 172 m

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Subject: Time and Distance

Q:

In a public bathroom there are n taps 1,2,3...n. Tap1 and Tap2 take equal time to fill the tank while Tap3 takes half the time taken by Tap2 and Tap4 takes half the time taken by Tap3. Similarly each next number of tap takes half the time taken by previous number of Tap i.e, K-th Tap takes half the time taken by (K-1)th Tap. If the 10th tap takes 2 hours to fill the tank alone then what is the ratio of efficiency of 8th tap and 12th tap, respectively?

A) 4:1	B) 5:3
C) 16:1	D) 1:16

Answer & Explanation Answer: D) 1:16

Explanation:

Time taken by 8th tap = 2 x 2 x 2= 8 hours

Time taken by 12th tap = 2x (1/2) x (1/2) = 1/2 hour

Ratio of time taken by 8th tap and 12th tap = 8 : 1/2 =16:1

Therefore, Ratio of efficiencies of 8th tap and 12th tap =1:16

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Filed Under: Time and Work

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