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Q:

Arjun and Bhishma are running on a circular track of length 600m. Speed of Arjun is 30 m/s and that of Bhishma is 20 m/s .They start fro the same point at the same time in the same direction. When will they meet again for the first time? 

Answer:



Sol : Time = Circumference Relative Speed = 60010 = 60 sec.


 


Actually Arjun has to make a lead of 600 m, because when Arjun will be 600m ahead of Bhishma, they will be together again as a person when completes the total length it starts retracing he same path and thus Arjun and Bhishma can be together again.


 


Since , they make  a difference of 10 m in 1 second. so, he will create 600m difference in 60 second.
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Karthik walks at 5 km/hr and reaches his destination 8 min late. If he walks at 6 km/hr, he reaches his destination on time. What distance he will cover in given time ?

A) 10 kms B) 8 kms
C) 6 kms D) 4 kms
 
Answer & Explanation Answer: D) 4 kms

Explanation:

Let the actual distance be t kms

Now, According to the data,

 

5t + 860 = 6t=> 560t + 860 = 6t=> 60t + 8 = 72t=> 8 = 12t=> t = 8/12 = 2/3 hrs

 

Now, the total distance = 6t = 6 x 2/3 = 2 x 2 = 4 kms.

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Q:

Two cars, a Maruthi and a Toyato, start at the same time in opposite directions from two distinct points A and B. Starting from A, the Maruthi reaches B in 6 hrs 20 minutes and the Toyato starting from B, reaches A in 4 hrs 45 minutes. What is the speed of the Toyato, if the speed of the Maruthi is 60 Km/h?

A) 75 kmph B) 80 kmph
C) 86 kmph D) 90 kmph
 
Answer & Explanation Answer: B) 80 kmph

Explanation:

Let the distance between A and B = D

Given the speed of maruthi = 60 kmph

Maruthi reaches from A to B in 6 hrs 20 min = 6 + 20/60 = 6 1/3 hrs

Now, the distance between A & B = D = speed x time = 60 x 19/3 = 380 kms

As the distance is same for toyato also,

given time for toyato = 4 hrs 45 min = 4 + 45/60 = 4 3/4 = 19/4 hrs

speed of toyato = distance/time = 380/19/4 = 380 x 4/19 = 80 kmph.

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A bike runs at the speed of 35 km/h when not serviced and runs at 55 km/h, when serviced. After servicing the bike covers a certain distance in 5 h. How much approximate time will the bike take to cover the same distance when not serviced?

A) 8 hrs B) 7.5 hrs
C) 7 hrs D) 6.5 hrs
 
Answer & Explanation Answer: A) 8 hrs

Explanation:

Given speed of the bike after servicing = 55 kmph

Time taken for travelling some distance at 55 kmph = 5 hrs

Then, 

Distance = Speed x Time = 55 x 5 = 275 kms.

Now, 

Speed of the bike before servicing = 35 kmph

Distance = 275 kms

Now, Time = Distance/Speed = 275/35 = 7.85 hrs =~ 8 hrs.

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Akhil after travelling 50 km meets Raju who suggests him to go slower. He then proceeds at ¾ of his former speed and arrives at his destination 35 minutes late. Had the meeting occurred 24 km further Akhil would have reached its destination 25 minutes late. What is the initial speed of Akhil?

 

A) 48 kmph B) 36 kmph
C) 24 kmph D) 20 kmph
 
Answer & Explanation Answer: A) 48 kmph

Explanation:

Let the initial speed of Akhil be '4p' kmph

Then speed after decrease in speed = '3p' kmph

We know that, 

Change in speed == Change in time

According to the given data,

243p - 244p = 35 - 2560=> p = 12

 

Hence, the initial speed of Akhil = 4p = 4 x 12 = 48 kmph.

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A 200 m long train passes a motorcycler, running in the same direction at 12 km/hr, in 15 second and a jeep travelling in the same direction in 20 s. At what speed is the car travelling (length of both the motorcycler and jeep is negligible)?

A) 36 kmph B) 32 kmph
C) 29 kmph D) 24 kmph
 
Answer & Explanation Answer: D) 24 kmph

Explanation:

Let the speed of the train be 'S' kmph

From the given data,

Distance = Length of train = D = 200 mts = 200 x 18/5 kms

Time = 10 sec

given speed of the motorcycler = 12 kmph

Relative speed as they are moving in the same direction = (S - 12) kmph

(S- 12) = 200 x 18515S - 12 = 48S = 60 kmph 

Hence, the speed of the train = S = 60 kmph

Now,

Let the speed of the jeep be 'x' kmph

60 - x = 200 x 1852060 - x = 36x = 60 - 36x = 24 kmph

 

Therefore, the speed of the jeep = x = 24 kmph.

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Buses start from a bus terminal with a speed of 20 km/hr at intervals of 10 minutes. What is the speed of a man coming from the opposite direction towards the bus terminal if he meets the buses at intervals of 8 minutes?

A) 5 kmph B) 6 kmph
C) 7.5 kmph D) 8 kmph
 
Answer & Explanation Answer: A) 5 kmph

Explanation:

Let p be the speed of man in kmph

According to the given data in the question,

Distance travelled by bus in 10 min with 20 kmph == Distance travelled by man in 8 min with (20 + p) kmph in opposite direction

=> 20 x 10/60 = 8/60 (20 + p)

=> 200 = 160 + 8p

=> p = 40/8 = 5 kmph.

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Q:

With an average speed of 40 km/hr, a train reaches its destination in time. If it goes with an average speed of 35 km/hr, it is late by 15 minutes. Find the length of the total journey?

A) 70 kms B) 60 kms
C) 45 kms D) 30 kms
 
Answer & Explanation Answer: A) 70 kms

Explanation:

Let the time taken by train be 't' hrs.

Then,

40t = 35t + 1560

40t = 35t + 35/4

t = 7/4 hrs

Therefore, Required length of the total journey d = s x t

= 40 x 7/4

= 70 kms.

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Ashwin fires two bullets from the same place at an interval of 15 minutes but Rahul sitting in a bus approaching the place hears the second sound 14 minutes 30 seconds after the first. If sound travels at the speed of 330 meter per second, what is the approximate speed of bus?

A) 330/29 m/s B) 330 x 30 m/s
C) 330/14 m/s D) 330/900 m/s
 
Answer & Explanation Answer: A) 330/29 m/s

Explanation:

Second gun shot take 30 sec to reach rahul imples distance between two.

given speed of sound = 330 m/s

Now, distance = 330 m/s x 30 sec 

 

Hence, speed of the bus = d/t = 330x30/(14x60 + 30) = 330/29 m/s.

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