Investments ratio is = 3:1
Time period ratio is = 2:1

As they are proportional to gain

------
Gain ratio of Vishal and raghu = 6:1

But given Raghu got Rs. 4000, 

=? 1 ----- 4000
     7 -----    ?

=> Rs.28,000

The total gain = Rs.28,000

We cannot find out the answer because the number of days of the current month is not given.

Ratio of times taken by A and B = 100 : 130 = 10 : 13.
Suppose B takes x days to do the work.

Then, 10 : 13 :: 23 : x     =>     x = ( 23 x 13/10 )     =>     x = 299 /10.

A's 1 day's work = 1/23 ;
B's 1 day's work = 10/299 .

(A + B)'s 1 day's work = ( 1/23 + 10/299 ) = 23/299 = 113 .

Therefore, A and B together can complete the work in 13 days. 

The Indian Institute of Technology (IIT) Kharagpur has collaborated with the British Geological Survey (BGS) to turn Varanasi into a smart city. As part of the project, three dimensional geological modelling of the geology under Varanasi will be prepared to help improve the building of new transport and service infrastructure. The project includes application of geo-scientific methods like drilling, geological, geophysical, tectonics, hydrogeological and remote sensing. It would be the first major 3D subsurface urban study and planning of its kind in India, with the ultimate aim of developing methodologies and input of suburban geology for planning and hazard risk assessment. The purpose of the project is to develop the methodologies and approaches of urban geosciences and engineering of Varanasi as a pilot for other Indian cities.

Two times IPL champions Mumbai Indians (MI) reached a new milestone as they became the first team in history to win 100 T20 matches. The Mumbai outfit defeated Kolkata Knight Riders (KKR) at the Eden Gardens by 9 runs in their final match of the league stage of IPL 2017.

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Let P's speed = x km/hr. Then, Q's speed = (7 - x) km/ hr.

So, 24/x + 24/(7 - x) = 14

x2 - 98x + 168 = 0

(x - 3)(x - 4) = 0 => x = 3 or 4.

Since, P is faster than Q,

so P's speed = 4 km/hr and Q's speed = 3 km/hr.

Let the speeds of the two trains be x m/sec and y m/sec respectively.

Then, length of the first train = 27 x meters, and

length of the second train = 17 y meters.

(27 x + 17 y) / (x + y) = 23

=> 27 x + 17 y = 23 x + 23 y

=> 4 x = 6 y

=> x/y = 3/2.