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Q:

Determine which of the given conclusions logically follows from the given statements, disregarding commonly known facts.

Statements:
Some actors are singers.
All the singers are dancers.

Conclusions:
(i) Some actors are dancers.
(ii) No singer is an actor.

A) Neither (i) nor (ii) follows	B) Either (i) or (ii) follows
C) Only conclusion (ii) follows	D) Only conclusion (i) follows

Answer & Explanation Answer: D) Only conclusion (i) follows

Explanation:

Some + All = Some

and the common word in two statements is Singers will not be used.

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Filed Under: Verification of Truth of the statement
Exam Prep: CAT
Job Role: Bank PO

Q:

In certain code, TOGETHER is written as TCJRGEQR. In the same code JOINING will be written as?

A) EPGPGQH	B) QHPGPGE
C) HQGPGPE	D) EGPGPHQ

Answer & Explanation Answer: A) EPGPGQH

Explanation:

The letters at odd positions are each moved two steps backward and those at even positions are each moved two steps forward and the obtained code is reversed to get the corresponding letters of the code.

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Filed Under: Coding and Decoding
Exam Prep: CAT
Job Role: Bank PO

Q:

What should be the maximum value of B in the following equation?
8A9 – 6B2 + 4C6 = 723

A) 4	B) 1
C) 5	D) 7

Answer & Explanation Answer: D) 7

Explanation:

1 1
8 A 9
+ 4 C 6
- 6 B 2
7 2 3
We may represent the given sum, as shown below:

1 + A + C - B = 12
A + C - B = 11

Now,giving the maximum values to A and C, i.e.

A = 9 and C = 9, we get B = 7.

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Filed Under: Numbers
Exam Prep: CAT
Job Role: Bank Clerk

Q:

The profit earned by selling an article for Rs.753 is equal to the loss incurred when the same article is sold for Rs.455.What should be the sale price for making 50% profit ?

A) Rs.855	B) Rs.955
C) Rs.906	D) Rs.896

Answer & Explanation Answer: C) Rs.906

Explanation:

Let C.P =Rs. x

Then as given, (753 - x ) = (x - 455)

=>2x = 1208 => x = 604

There fore S.P= 150% of 604 => Rs. $\frac{150}{100} \times 604$ = Rs.906

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Filed Under: Profit and Loss
Exam Prep: CAT
Job Role: Bank PO

Q:

Two trains 85 m and 75 m long are running in same direction with speeds of 62 km/hr and 44 km/hr respectively. In what time will the first train cross the second train ?

A) 22 sec	B) 32 sec
C) 42 sec	D) 52 sec

Answer & Explanation Answer: B) 32 sec

Explanation:

Given that,

1st train speed = 62 km/hr

2nd train speed = 44 km/hr

Hence the relative speed of two trains is : 62-44 = 18 km/hr = $18 \times \frac{5}{18}$ m/s = 5 m/s.

There fore, the first train crosses the second train i.e (85+75)mts of distance with a speed of 5m/s in,

time = $\frac{d i s \tan c e}{s p e e d} = \frac{85 + 75}{5}$ = 32 sec.

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Filed Under: Time and Distance
Exam Prep: CAT
Job Role: Bank Clerk

Q:

A sales boy is allowed $4 \frac{1}{2}$ % discount on the total sales made by him plus a bonus of $\frac{1}{4}$ % on the sales over Rs.12,000.If his total earnings were Rs.2400, then his total sales(in Rs.) are ?

A) Rs.60,145.23	B) Rs.54,285.54
C) Rs.52,147.85	D) Rs.50,589.47

Answer & Explanation Answer: D) Rs.50,589.47

Explanation:

Let the total earnings be Rs.x

Then $4 \frac{1}{2}$ % of x + $\frac{1}{4}$ % of (x-12000) =2400

$\Rightarrow \frac{9}{2} \times \frac{x}{100} + \frac{1}{4} \times \frac{x - 12000}{100} = 2400$

=> x=50,589.47

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Filed Under: Percentage
Exam Prep: CAT
Job Role: Bank Clerk

Q:

Which one of the following orders presents the correct sequence of the increasing basic nature of the given oxides?

(1) $K_{2} O < N a_{2} O < A l_{2} O_{3} < M g O$

(2) $A l_{2} O_{3} < M g O < N a_{2} O < K_{2} O$

(3) $M g O < K_{2} O < A l_{2} O_{3} < N a_{2} O$

(4) $N a_{2} O < K_{2} O < M g O < A l_{2} O_{3}$

A) Option 1	B) Option 2
C) Option 3	D) Option 4

Answer & Explanation Answer: B) Option 2

Explanation:

While moving from left to right in periodic table basic character of oxide of elements will decrease.

$∴ \to_{I n c r e a \sin g b a s i c s t r e n g t h}^{A l_{2} O_{3} < M g O < N a_{2} O}$

and while descending in the group basic character of corresponding oxides increases.

$∴ \to_{I n c r e a \sin g b a s i c s t r e n g t h}^{N a_{2} O < K_{2} O}$

$∴ C o r r e c t O r d e r i s A l_{2} O_{3} < M g O < N a_{2} O < K_{2} O$

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Filed Under: Chemistry
Exam Prep: AIEEE

Q:

Boron cannot form which one of the following anions?

(1) $B O_{2}^{-}$

(2) $B F_{6}^{3 -}$

(3) $B H_{4}^{-}$

(4) $B (O H)_{4}^{-}$

A) Option 1	B) Option 2
C) Option 3	D) Option 4

Answer & Explanation Answer: B) Option 2

Explanation:

Due to absence of low lying vacant d orbital in B, $s p^{3} d^{2}$ hybridization is not possible hence $B F_{6}^{3 -}$ will not formed.

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Filed Under: Chemistry
Exam Prep: AIEEE

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