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Q:

In the question, two equations I and II are given. You have to solve both the equations and give answer

x2-11x+28=0y2-18y+81=0

A) x > y B) x < y
C)  x=y, or relation cannot be established between x and y D) x ≥ y
 
Answer & Explanation Answer: B) x < y

Explanation:

x2 – 11x + 28=0

x2 – 7x – 4x + 28=0

x (x-7) – 4 (x-7)=0

(x-4) (x-7)=0 x=4, 7

y2 – 18y + 81=0

y2 –9y – 9y + 81=0

y (y-9) – 9 (y-9)=0

(y-9) (y-9)=0 y=9, 9

So, x<y.

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Filed Under: Simplification

Q:

3x2-14x+16=05y2-16y+12=0

A) x > y B) x < y
C) x=y or relation cannot be established between x and y D) x ≥ y
 
Answer & Explanation Answer: C) x=y or relation cannot be established between x and y

Explanation:

3x2 – 14x + 16=0

3x2 –6x – 8x + 16=0

3x (x-2) – 8 (x-2)

(3x-8) (x-2)=0

x=8/3 or 2

5y2 – 16y + 12=0

5y2 – 10y – 6y + 12=0

5y (y-2) – 6 (y-2)=0

(5y-6) (y-2)=0

y=6/5 or 2

Can't be determined.

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Q:

In each of these questions, two equations (I) and (II) are given.

I. 2x2+19x+42 = 0II. 4y2+43y+30 = 0

A)  x > y B) x < y
C)  x ≥ y D) x ≤ y
 
Answer & Explanation Answer:

Explanation:

I. 2x2 + 19x + 42 = 0

2x2 + 12x + 7x + 42 = 0

2x (x+6) + 7(x +6) = 0

(2x+7) (x+6) = 0 x = -7/2, -6 I

I. 4y2 + 43y + 30 = 0

4y2 +40y + 3y + 30 = 0

4y(y + 10) + 3(y + 10) (4y + 3)(y + 10) = 0

y = -3/4, -10

So answer is no relation.

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Q:

In each of the following questions two equations I and II are given. Solve both the equations and give answer:
I. x2+2x-195=0II. y2+30y+225=0

A) x = y or relation can’t be established between x and y B) x > y
C)  x < y D)  x ≥ y
 
Answer & Explanation Answer: D)  x ≥ y

Explanation:

 I. x2 + 2x - 195 = 0 = (x+15) (x-13) => x = -15, 13

II. y2 + 30y + 225 = 0 = (y+15) (y+15) => y = -15, -15

So x ≥ y

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Q:

In the question given below, two equations are provided. Solve the equations and establish the relationship between x and y

I. 2x2-13x-189=0 II. 2y2-3y-189=0

A) x>y B)  x≥y
C)  x<y D) x≤y
 
Answer & Explanation Answer:

Explanation:

I. 2x2 - 13x - 189 = 0 2x2 - 27x + 14x - 189 = 0 x(2x - 27) + 7(2x - 27) = 0 x = -7, 27/2

II. 2y2 - 3y - 189 = 0 2y2 - 21y + 18y - 189 = 0 y(2y - 21) + 9(2y - 21) = 0 y = -9, 21/2

When x, as well as y, have both positive and negative values then no relationship can be established between them because if we consider x to be positive then the negative value of y will be lesser than x. If we consider x to be negative then positive value of y will be greater than x.

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Q:

The ages of Sunil and Anil are in the ratio 8:7, after 6 years, the ratio of their ages will be 19 : 17. What is the difference in their present ages?

A) 10 years B) 6 years
C) 8 years D) 4 years
 
Answer & Explanation Answer: D) 4 years

Explanation:

suppose the ages of Sunil and Anil are 8x yr and 7x yr, respectively.
After 6 yr, = 136x + 102 = 133x + 114
136x – 133x = 114 – 102
3x = 12 X = 12/3 = 4
Age of Sunil = 8x = 8 × 4 = 32 yr
Present age Anil = 7x = 7 × 4 = 28 yr
Required difference = (32 – 28) = 4 yr

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Exam Prep: Bank Exams

Q:

What should come in place of question mark (?) in the following question?

65% × 700 + √196 – 9 × 3 = ?

A) 522 B) 442
C) 402 D) 362
 
Answer & Explanation Answer: B) 442

Explanation:

As per the BODMAS rule, Addition and subtraction can be treated on same priority (from left to right) when they are in consecutive order.

65% × 700 + 14 - 9 × 3 65 × (700/100) + 14 - 27 455 + 14 - 27 = 442

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Exam Prep: AIEEE , Bank Exams , CAT

Q:

What should come in place of question mark (?) in the following question?

12.5 × 3.2 × 8.8 = ?

A) 358 B) 355
C) 354 D) 356
 
Answer & Explanation Answer:

Explanation:

12.5 × 3.2 × 8.8 = 352

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