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Q:

A high growth rate of population is characterised by

A) High birth and high death rate B) High birth and low death rate
C) Low birth and low death rate D) Low birth and high death rate
 
Answer & Explanation Answer: B) High birth and low death rate

Explanation:
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Filed Under: Indian Economy

Q:

Which among the following keys are used to identify each row of the table uniquely?

A) Primary key B) Unique key
C) Partial key D) None of the above
 
Answer & Explanation Answer: A) Primary key

Explanation:

Primary key helps us to identify a row uniquely in a relation

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Q:

Kramer borrowed $4000 from George at an interest rate of 7% compounded semiannually. The loan is to be repaid by three payments. The first payment, $1000, is due two years after the date of the loan. The second and third payments are due three and five years, respectively, after the initial loan. Calculate the amounts of the second and third payments if the second payment is to be twice the size of the third payment.

A) 1389 B) 1359
C) 1379 D) 1339.33
 
Answer & Explanation Answer: D) 1339.33

Explanation:

Given:j=7% compounded semiannually making m=2 and i = j/m= 7%/2 = 3.5%
Let x represent the third payment. Then the second payment must be 2x.
PV1,PV2, andPV3 represent the present values of the first, second, and third payments.

Since the sum of the present values of all payments equals the original loan, then
PV1 + PV2  +PV3  =$4000 -------(1)

PV1   =FV/(1 + i)^n  =$1000/(1.035)^4=  $871.44

At first, we may be stumped as to how to proceed for
PV2 and PV3. Let’s think about the third payment of x dollars. We can compute the present value of just $1 from the x dollars

pv=1/(1.035)^10=0.7089188

PV2   =2x * 0.7089188 = 1.6270013x
PV3   =x * 0.7089188=0.7089188x
Now substitute these values into equation ➀ and solve for x.
$871.442 + 1.6270013x + 0.7089188x  =$4000

2.3359201x  =$3128.558

x=$1339.326
Kramer’s second payment will be 2($1339.326)  =$2678.65, and the third payment will be $1339.33

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Filed Under: Compound Interest
Exam Prep: Bank Exams
Job Role: Bank PO

Q:

In how many ways can 4 girls and 5 boys be arranged in a row so that all the four girls are together ?

A) 18000 B) 17280
C) 17829 D) 18270
 
Answer & Explanation Answer: B) 17280

Explanation:

Let 4 girls be one unit and now there are 6 units in all.

 

They can be arranged in 6! ways.

 

In each of these arrangements 4 girls can be arranged in 4! ways. 

 

Total number of arrangements in which girls are always together = 6! x 4!= 720 x 24 = 17280

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Q:

In how many ways can an animal trainer arrange 5 lions and 4 tigers in a row so that no two lions are together?

A) 2800 B) 2880
C) 2600 D) 3980
 
Answer & Explanation Answer: B) 2880

Explanation:

They have to be arranged in the following way :

                                                                    L  T  L  T  L  T  L  T  L

The 5 lions should be arranged in the 5 places marked ‘L’.

This can be done in 5! ways.

The 4 tigers should be in the 4 places marked ‘T’.

This can be done in 4! ways.

Therefore, the lions and the tigers can be arranged in 5!´ 4! ways = 2880 ways.

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Q:

A small text file on the client machine either in the client’s file system or memory of client browser session is called

A) View State B) Cookies
C) QueryString D) None
 
Answer & Explanation Answer: B) Cookies

Explanation:

A cookie is a small text file on the client machine either in the client’s file system or memory of client browser session.

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Filed Under: .NET
Job Role: Software Architect

Q:

if log105+log5x+1=log10(x+5)+1,then x is equal to

A) 1 B) 3
C) 5 D) 10
 
Answer & Explanation Answer: B) 3

Explanation:

log105+log5x+1=log10x+5+1

log1055x+1=log1010x+5

55x+1=10x+5

5x+1=2x+10

3x=9

x=3

 

 

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Filed Under: Logarithms
Exam Prep: Bank Exams
Job Role: Bank PO

Q:

What is the probability of getting a sum 9 from two throws of a dice ?

A) 1/6 B) 1/2
C) 1/9 D) 3/4
 
Answer & Explanation Answer: C) 1/9

Explanation:

In two throws of a die, n(s)=(6 x 6)=36

 

let E= Event of geting a sum 9={(3,6),(4,5),(5,4),(6,3)}

 

P(E) = n(E)/n(S) = 4/36 = 1/9

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Filed Under: Probability