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Q:

Which of the following is used in pencils?

A) Silicon	B) Phosphorous
C) Graphite	D) Charcoal

Answer & Explanation Answer: C) Graphite

Explanation:

A pencil is an implement for writing or drawing. It is a thin core of graphite well mixed with clay, inside a wooden body as protective casing that prevents the core from being broken.

Which_of_the_following_is_used_in_pencils1558506948.jpg image

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Filed Under: General Science
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Q:

Den Bosch and Eastbourne are two famous cities 300 km apart. Maradona starts from Den Bosch at 8:24 am . An hour later pele starts from Den Bosch. After travelling for 1 hour , Pele reaches Nottingham that Maradona had passed 40 minutes earlier. Nottingham falls on the way from Den Bosch to Eastbourne. If pele and Maradona just reaches Eastbourne at the same time, what are thespeeds of the Maradona and Pele Respectively?

A) 100 km/h , 125 km/h	B) 60 km/h , 80 km/h
C) 60 km/h , 75 km/h	D) 75 km/h , 100 km/h

Answer & Explanation Answer: D) 75 km/h , 100 km/h

Explanation:

Let Pele x km in 1 hour. so Maradona takes (2h-40min)=1 h 20 min to cover x km. Let speed of Maradona and Pele be M and P respectively than

x =M x (4/3) and x= P x 1

=> M/P = 3/4

Again $\frac{300}{M} = \frac{300}{P} = 1$

$\Rightarrow \frac{300}{3 k} - \frac{300}{4 k} = 1$

=> k= 25

M= 3k = 75 km/h and P= 4k = 100 km/h

( Through options it is very easy to solve)

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Filed Under: Time and Distance

Q:

Two horses start trotting towards each other, one from A to B and another from B to A. They cross each other after one hour and the first horse reaches B, 5/6 hour before the second horse reaches A. If the distance between A and B is 50 km. what is the speed of the slower horse?

A) 30 km/h	B) 15 km/h
C) 25 km/h	D) 20 km/h

Answer & Explanation Answer: D) 20 km/h

Explanation:

If the speed of the faster horse be $f_{s}$ and that of slower horse be $s_{s}$ then

$f_{s} + s_{s} = \frac{50}{1} = 50$

and $\frac{50}{s_{s}} - \frac{50}{f_{s}} = \frac{5}{6}$

Now, you can go through options.

The speed of slower horse is 20km/h

Since, 20+30=50

and $\frac{50}{20} - \frac{50}{30} = \frac{5}{6}$

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Filed Under: Time and Distance

Q:

A train overtakes two girls who are walking in the opposite direction in which the train is going at the rate of 3 km/h and 6km/h and passes them completely in 36 seconds and 30 seconds respectively. The length of the train is:

A) 120m	B) 150m
C) 125m	D) None of these

Answer & Explanation Answer: B) 150m

Explanation:

Let the length of the train e x meter, and let the speed of train be y km/h, then

$x = (y + 3) \times \frac{5}{18} \times 36$ --------(1) and

$x = (y + 6) \times \frac{5}{18} \times 30$ ---------(2)

From eq (1) and (2), we get

y = 12 km/h

Therefore, $x = (y + 3) \times \frac{5}{18} \times 36$ => x= 150 m

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Filed Under: Time and Distance

Q:

A person goes to his office at 1/3rd of the speed at which he returns from his office. If the average speed during the whole trip is 12 m /h . what is the speed of the person while he was going to his office?

A) 10	B) 6
C) 8	D) can't be determined

Answer & Explanation Answer: C) 8

Explanation:

u = k , v= 3k

$∴ \frac{2 u v}{u + v} \Rightarrow \frac{2 \times k \times 3 k}{(k + 3 k)} = 12$ => k = 8km/h

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Q:

In a one km race A gives B a start of 100m and in a one km race B gives a start of 80 m to C. In a 1 km race who will win and by how much distance from the worst performer between two losers?

Answer

Ratio of speeds of A:B = 1000:900 = 100:90

Ratio of speeds of B:C = 1000:920 = 100:92

Therefore, when A moves 1000m , B moves 900 m and when B moves 900m, C moves 828m

Thus, $\begin{matrix} \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; 828m\; \; \;\; \; 900m\;\; \; \; \; 1000m\\ A...............|........|..........|\\ \; \; \; \;\; \; \; \; \; \; \; \; \; \; \; \; \; C\; \; \; \; \; \; \; \; B\; \; \; \; \; \; \; \; \; A \end{matrix}$

Since , C moves 8 % less than B in the same time . Thus, C is the worst performer and A will win by him by 172 m

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Subject: Time and Distance

Q:

A contractor undertook a project to complete it in 20 days which needed 5 workers to work continuously for all the days estimated. But before the start of the work the client wanted to complete it earlier than the scheduled time, so the contractor calculated that he needed to increase 5 additional men every 2 days to complete the work in the time the client wanted it:

If the work was further increased by 50% but the contractor continues to increase the 5 workers o every 2 days then how many more days are required over the initial time specified by the client.

A) 1 day	B) 2 days
C) 5 days	D) None of these

Answer & Explanation Answer: B) 2 days

Explanation:

Total work = 100+50 = 150man-days

In 8 days 100 man-days work has been completed. Now on 9th and 10th day there will be 25 workers. So in 2 days they wll complete additional 50 man- days work. Thus the work requires 2 more days.

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Filed Under: Time and Work

Q:

In a public bathroom there are n taps 1,2,3...n. Tap1 and Tap2 take equal time to fill the tank while Tap3 takes half the time taken by Tap2 and Tap4 takes half the time taken by Tap3. Similarly each next number of tap takes half the time taken by previous number of Tap i.e, K-th Tap takes half the time taken by (K-1)th Tap. If the 10th tap takes 2 hours to fill the tank alone then what is the ratio of efficiency of 8th tap and 12th tap, respectively?

A) 4:1	B) 5:3
C) 16:1	D) 1:16

Answer & Explanation Answer: D) 1:16

Explanation:

Time taken by 8th tap = 2 x 2 x 2= 8 hours

Time taken by 12th tap = 2x (1/2) x (1/2) = 1/2 hour

Ratio of time taken by 8th tap and 12th tap = 8 : 1/2 =16:1

Therefore, Ratio of efficiencies of 8th tap and 12th tap =1:16

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Filed Under: Time and Work

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