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Q:

In a wheelchair slalom event, athletes weave around cones and race to the finish line. A diagram of the rectangular course is shown. Find the perimeter of the course

A) 32	B) 42
C) 62	D) 92

Answer & Explanation Answer: D) 92

Explanation:

P = 2l + 2w

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Q:

Find the area of the rectangle or square with the given dimensions L = 5 inches, W= 3 inches?

A) 13	B) 14
C) 15	D) 16

Answer & Explanation Answer: C) 15

Explanation:

We know that,

Area of rectangle A = L x W = 5 x 3 = 15 sq.inches.

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Q:

The area of a square is 49 mm. What is the length of each side?

A) 5mm	B) 6mm
C) 7mm	D) 8mm

Answer & Explanation Answer: C) 7mm

Explanation:

$A = S^{2}$

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Q:

Find the length of a rope by which a cow must be tethered in order that it may be able to graze an area of 9856 sq meters.

A) 56m	B) 16m
C) 14m	D) 76m

Answer & Explanation Answer: A) 56m

Explanation:

clearly the cow will graze a circular field of area 9856 sq m and radius equal to the length of the rope.

Let the length of the rope be r mts

then, ${πr}^{2} = 9856 \Rightarrow r^{2} = \frac{9856 \times 7}{22} = 3136 \Rightarrow r = 56 m$

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Q:

The cost of fencing a square field @ Rs. 20 per metre is Rs.10.080.How much will it cost to lay a three meter wide pavement along the fencing inside the field @ Rs. 50 per sq m

A) 53800	B) 43800
C) 83800	D) 73800

Answer & Explanation Answer: D) 73800

Explanation:

perimeter = total cost / cost per m = 10080 /20 = 504m
side of the square = 504/4 = 126m
breadth of the pavement = 3m
side of inner square = 126 - 6 = 120m
area of the pavement = (126 x126) - (120 x 120) = 246 x 6 sq m
cost of pavement = 246*6*50 = Rs. 73800

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Q:

A particle which is similar to electron is

A) positron	B) beta particle
C) photon	D) mason

Answer & Explanation Answer: B) beta particle

Explanation:

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Q:

A rectangular lawn 55m by 35m has two roads each 4m wide running in the middle of it. One parallel to the length and the other parallel to breadth. The cost of graveling the roads at 75 paise per sq meter is

A) rs.58	B) rs.158
C) rs.258	D) rs.358

Answer & Explanation Answer: C) rs.258

Explanation:

area of cross roads = (55 x 4) + (35 x 4)- (4 x 4) = 344sq m

cost of graveling = 344 x (75/100) = Rs. 258

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Q:

A rectangular paper when folded into two congruent parts had a perimeter of 34cm foer each part folded along one set of sides and the same is 38cm. When folded along the other set of sides. What is the area of the paper?

A) 140	B) 150
C) 160	D) 170

Answer & Explanation Answer: A) 140

Explanation:

when folded along the breadth
we have 2(l/2 +b) = 34 or l+2b = 34...........(1)
when folded along the length, we have 2(l+b/2)=38 or 2l+b =38.....(2)
from 1 &2 we get l=14 and b=10
Area of the paper = 14*10 = 140 sq cm

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