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Q:

Namitha sold a powerbank which is at the cost of Rs. 1950 at a loss of 25%. Find at what cost will she have to sell it to get a profit of 25%?

A) Rs. 3680	B) Rs. 3560
C) Rs. 3320	D) Rs. 3250

Answer & Explanation Answer: D) Rs. 3250

Explanation:

Let the Cost price of the powerbank = Rs. P

But given that by selling it at Rs. 1950, it gives a loss of 25%

=> $\frac{P x 75}{100} = 1950$
=> $P = \frac{1950 x 100}{75}$ = Rs. 2600
Now, to get a profit of 25%

Selling Price = $\frac{2600 x 125}{100} = Rs . 3250$ .

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Filed Under: Profit and Loss
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Q:

Which statement best describes an $O_{3}$ molecule?

A) The double bond in ozone switches back and forth between the two outer oxygen atoms	B) An ozone molecule contains one single bond and one double bond
C) Each atom in ozone is connected to another atom by 1.5 bonds.	D) None

Answer & Explanation Answer: B) An ozone molecule contains one single bond and one double bond

Explanation:

Ozone molecule has one single bond and one double bond.

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Filed Under: General Science
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Q:

What is the IUPAC name for the following compound?

$H_{3} C - C \equiv C - H$

A) Acetylene	B) Methyl acetylene
C) Butanol	D) Decanoic Acid

Answer & Explanation Answer: B) Methyl acetylene

Explanation:

The IUPAC name of the compound is Methyl Acetylene or Propyne.

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Filed Under: Chemistry
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Q:

Oxidation Number of 'S' in $H_{2} S O_{4}$ ?

A) +6	B) +2
C) -6	D) -2

Answer & Explanation Answer: A) +6

Explanation:

In $H_{2} S O_{4}$ ,

Hydrogen has a charge of +2, with each hydrogen has +1.

Oxygen has a charge of -8, with each oxugen has -2.

Total charge = (2 - 8) = -6

Therefore, the Oxidation number of Sulphur S is '+6' because to make the compound stable.

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Filed Under: Chemistry
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Q:

Can you Solve $7 + 7 \div 7 + 7 x 7 + 7 - 7 \div 7 + 7 x 7$ =

A) 112	B) 56
C) 0	D) 98

Answer & Explanation Answer: A) 112

Explanation:

$7 + 7 \div 7 + 7 x 7 + 7 - 7 \div 7 + 7 x 7 = 7 + 1 + 49 + 7 - 1 + 49 = 8 + 56 + 48 = 56 + 56 = 112$

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Filed Under: Mathematical Operations
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Q:

What is consumption disease in the 19th century?

A) Tuberculosis	B) Paralysis
C) Plague	D) Cholera

Answer & Explanation Answer: A) Tuberculosis

Explanation:

Tuberculosis (TB) was the leading cause of death in the United States and one of the most feared diseases in the world during the 19th and early 20th centuries.

Formerly known as Consumption diseases because many types of lung diseases were lumped under the term 'consumption'. Lung cancer and bronchitis were examples.

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Filed Under: Indian History
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Q:

The last two digits of $2151^{415}$ ?

A) 81	B) 61
C) 91	D) 51

Answer & Explanation Answer: D) 51

Explanation:

Unit digit of this expression is always 1 as the base ends with 1.

For the tenth place digit we need to multiply the digit in the tenth place of the base and unit digit of the power and take its unit digit.

i.e, tenth place digit in 2151 is 5 and

tenth place digit in power 415 is 1

And the units digit in the product of 5 x 1 = 5

Therefore, last two digits of $2151^{415}$ is 51.

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Filed Under: Mathematical Operations
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Q:

$112 \times 5^{4} =$

A) 68947	B) 69874
C) 70000	D) 76000

Answer & Explanation Answer: C) 70000

Explanation:

$112 \times 5^{4} 112 \times {(\frac{10}{2})}^{4} = \frac{112 \times 10000}{2^{4}} = 1120000 / 16$

= 70,000.

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Filed Under: Simplification
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