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Q:

The inner circumference of a circular race track, 14m wide is 440m. Find the radius of the outer circle.

A) 84m B) 24m
C) 44m D) 54m
 
Answer & Explanation Answer: A) 84m

Explanation:

let inner radius be r meters. 

2πr=440r=440×744=70mradius of outer circle =70+14m  

 

Therefore, Radius of outer circle = 70 + 14 = 84m

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Q:

A sector of 120, cut out from a circle, has an area of 667cm2. Find the radius of the circle ?

A) 1 B) 2
C) 3 D) 4
 
Answer & Explanation Answer: C) 3

Explanation:

Let the radius of the circle be r cm. Then, 

 

120360πr2=667 

 

r2=667*722*3 

 

r=3.

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Q:

Two concentric circles form a ring. The inner and outer circumferences of ring are  5187m and 3527 m respectively. Find the width of the ring.

A) 4 B) 5
C) 6 D) 7
 
Answer & Explanation Answer: A) 4

Explanation:

Let the inner and outer radii be r and R metres.

 

Then  2πR=3527=>R=3527*722*12=8m 

 

 2πR=5287=>R=5287*722*12=12m

 

=> Width of the ring = (R - r) = (12 - 8) m = 4 m.

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Q:

The inner circumference of a circular race track, 14 m wide, is 440 m. Find radius of the outer circle

A) 44 B) 22
C) 33 D) 84
 
Answer & Explanation Answer: D) 84

Explanation:

Let inner radius be r metres. Then, 2πr = 440 ; r = 440×744= 70 m.

Radius of outer circle = (70 + 14) m = 84 m.

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Q:

The diagonal of the floor of a rectangular closet is 712 feet. The shorter side of the closet is 412 feet. What is the area of the closet in square feet?

A) 9 B) 18
C) 27 D) 36
 
Answer & Explanation Answer: C) 27

Explanation:

Other side = d2-s22254-814 = 1444 = 6 ft

 

  Area of closet = (6 x 4.5) sq. ft = 27 sq. ft.

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Q:

What is the difference between oracle,sql and sql server?

Answer

  • Oracle is based on RDBMS.

  • SQL is Structured Query Language.

  • SQL Server is another tool for RDBMS provided by MicroSoft


 

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Q:

What is an Oracle index?

Answer

An index is an optional structure associated with a table to have direct access to rows, which can be created to increase the performance of data retrieval. Index can be created on one or more columns of a table.

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Q:

Goldenrod and No Hope are in a horse race with 6 contestants. How many different arrangements of finishes are there if No Hope always finishes before Goldenrod and if all of the horses finish the race?

A) 720 B) 360
C) 120 D) 640
 
Answer & Explanation Answer: B) 360

Explanation:

Two horses A and B, in a race of 6 horses... A has to finish before B

 

if A finishes 1... B could be in any of other 5 positions in 5 ways and other horses finish in 4! Ways, so total ways 5*4!

 

if A finishes 2... B could be in any of the last 4 positions in 4 ways. But the other positions could be filled in 4! ways, so the total ways 4*4!

 

if A finishes 3rd... B could be in any of last 3 positions in 3 ways, but the other positions could be filled in 4! ways, so total ways 3*4!

 

if A finishes 4th... B could be in any of last 2 positions in 2 ways, but the other positions could be filled in 4! ways, so total ways... 2 * 4! 

 

if A finishes 5th .. B has to be 6th and the top 4 positions could be filled in 4! ways..

 

A cannot finish 6th, since he has to be ahead of B

 

Therefore total number of ways = 5*4! + 4*4! + 3*4! + 2*4! + 4! = 120 + 96 + 72 + 48 + 24 = 360

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