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Q:

The ratio of present ages of Hema and Chinnu is 13:17. Four years ago the ratio of their ages was 11:15. What will be the ratio of their ages six years hence ?

A) 3 : 7 B) 7 : 9
C) 4 : 5 D) 1 : 3
 
Answer & Explanation Answer: C) 4 : 5

Explanation:

Let their present ages be 13x and 17x.
Then, 13x-4/17x-4 = 11/15.
Solving this, we get x = 2.
Required ratio = 13x2 + 6/17x2 + 6 = 32/40 = 4/5.

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Filed Under: Problems on Ages
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Q:

A single pipe of diameter x has to be replaced by six pipes of diameters 12 cm each. The pipes are used to covey some liquid in a laboratory. If the speed/flow of the liquid is maintained the same then the value of x is ?

A) 14.69 cm B) 29.39 cm
C) 18.65 cm D) 22.21 cm
 
Answer & Explanation Answer: B) 29.39 cm

Explanation:

Volume of water flowing through 1 pipe of diameter x = Volume discharged by 6 pipes of diameter 12 cms.

 

As speed is same, area of cross sections should be same. 

 

Area of bigger pipe of diameter x = Total area of 6 smaller pipes of diameter 12 

i.e πR2 = 6πR12   

Here R = R and R1 = 12/2 = 6   

R2 = 6×6×6   

R = 14.696   

=> D = X = 14.696 * 2 = 29.3938 cm.

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Filed Under: Volume and Surface Area
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Q:

On a ruler's tombstone, it is said that one sixth of his life was spent in childhood and one twelfth as a teenager. One seventh of his life passed between the time he became an adult and the time he married; five years later, his son was born. Alas, the son died four years before he did. He lived to be twice as old as his son did. How old did the ruler live to be ?

A) 84 years B) 72 years
C) 82 years D) 64 years
 
Answer & Explanation Answer: A) 84 years

Explanation:

Let the age of ruler is x so that of son = x/2 (given)
Now according to the given condition
(x/6) + (x/12) + (x/7) + 5 + (x/2) + 4 = x
=> x = 84

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Q:

Out of sixty students, there are 14 who are taking Economics and 29 who are taking Calculus. What is the probability that a randomly chosen student from this group is taking only the Calculus class ?

A) 8/15 B) 7/15
C) 1/15 D) 4/15
 
Answer & Explanation Answer: B) 7/15

Explanation:

Given total students in the class = 60
Students who are taking Economics = 24 and
Students who are taking Calculus = 32
Students who are taking both subjects = 60-(24 + 32) = 60 - 56 = 4
Students who are taking calculus only = 32 - 4 = 28
probability that a randomly chosen student from this group is taking only the Calculus class = 28/60 = 7/15.

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Filed Under: Probability
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Q:

A group of six cousins are sitting around a hexagonal table, each one at one corner of the hexagon. (facing the centre inside) Raju is sitting opposite to Rohan. Sweety is sitting next to Navya. Aadya is sitting opposite to Navya, but not next to Kalyan. Karthik has a person sitting between Rohan and himself. If Sweety sits to the right of Karthik, then who is sitting to the left of Karthik ?

A) Aadya B) Kalyan
C) Raju D) Rohan
 
Answer & Explanation Answer: C) Raju

Explanation:

Suppose Sweety is sitting between Rohan and Karthik such that she is to the right of him.....then as Raju is opposite to Rohan then Raju must be to the left of Karthik.

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Filed Under: Logic
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Q:

A six-digit number is formed by repeating a three-digit number; for example, 404404 or 415415 etc. Any number of this form is always exactly divisible by 

A) 101 B) 901
C) 1001 D) 789
 
Answer & Explanation Answer: C) 1001

Explanation:

Here by trial and error method, we can obseve that

404404 = 404 x 1001; 415415 = 415 x 1001, etc.

So, any number of this form is divisible by 1001.

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Filed Under: Numbers
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Q:

Twelve children take sixteen days to complete a work which can be completed by 8 adults in 12 days. After working for 3 days, sixteen adults left and six adults and four children joined them. How many days will they take to complete the remaining work ?

A) 3 days B) 2 days
C) 6 days D) 12 days
 
Answer & Explanation Answer: C) 6 days

Explanation:

From the given data,

12 children 16 days work,
One child’s one day work = 1/192.


8 adults 12 days work,
One adult’s one day’s work = 1/96.


Work done in 3 days = ((1/96) x 16 x 3) = 1/2


Remaining work = 1 – 1/2 = 1/2


(6 adults+ 4 children)’s 1 day’s work = 6/96 + 4/192 = 1/12

1/12 work is done by them in 1 day.

1/2 work is done by them in 12 x (1/2) = 6 days.

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Filed Under: Time and Work
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Q:

In agroup of six women, there are four dancers, four vocal musicians, one actress and three violinists. Girija and Vanaja are among the violinists while Jalaja and Shailaja do not know how to ply on the violin. Shailaja and Tanuja are among the dancers. Jalaja, Vanaja, Shailaja and Tanuja are all vocal musicians and two of them are also violinists. If Pooja is an actress, who among the following is both a dancer and a violinist ?

A) Shailaja B) Vanaja
C) Girija D) Tanuja
 
Answer & Explanation Answer: D) Tanuja

Explanation:

The four vocal musicians and one actress in the group are given. Two dancers are Shailaja and Tanuja. Two violinists are Girija and Vanaja. Since Jalaja and Shailaja cannot be violinists, so remaining two violinists are Tanuja and Pooja. Clearly, Tanuja is both a violinist and a dancer.

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Filed Under: Deriving Conclusions From Passages
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