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Q:

If the selling price of a mat is five times the discount offered and if the percentage of discount is equal to the percentage profit, find the ratio of the discount offered to the cost price.

A) 6:31 B) 11:30
C) 7:30 D) 31:6
 
Answer & Explanation Answer: C) 7:30

Explanation:

Since S.P. = 5 (M.P. - S.P.) => 5 M.P. = 6 S.P.
M.P. = (6/5) S.P.
Since the percentage discount = Percentage profit,
65S.P - S.P65S.P×100 = S.P -C.PC.P×100
Therefore, 1/6 = (S.P/C.P) – 1 => S.P = (7/6) C.P
M.P = 6/5 S.P = 6/5 x 7/6 C.P = 7/5 C.P
Therefore, Ratio of discount to C.P
= (M.P – S.P)/C.P = [{(7/5)C.P - (7/6)C.P} / C.P.]
= 7/30

 

Therefore, the ratio is 7 : 30

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Filed Under: Profit and Loss
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Q:

Three maths classes: A, B and C take an algebra test. The average score of class A is 83. The average score of class B is 76. The average score of class C is 85. The average score of class A and B is 79 and average score of class B and C is 81. What is the average score of classes A, B, C ?

A) 81 B) 78
C) 80.5 D) 81.5
 
Answer & Explanation Answer: D) 81.5

Explanation:

Let the number of students in classes A, B and C be P, Q and R respectively.
Then, total score of A = 83P, total score of B = 76Q, total score of C = 85R.
Also given that,
(83P + 76Q) / (P + Q) = 79
=>4P = 3Q.
(76Q + 85R)/(Q + R) = 81
=>4R = 5Q,
=>Q = 4P/3 and R = 5P/3
Therefore, average score of A, B, C = ( 83P + 76Q + 85R ) / (P + Q + R) = 978/12 = 81.5

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Filed Under: Average
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Q:

Without any stoppage, a person travels a certain distance at an average speed of 42 km/h, and with stoppages he covers the same distance at an average speed of 28 km/h. How many minutes per hour does he stop?

A) 15 minutes B) 20 minutes
C) 18 minutes D) 22 minutes
 
Answer & Explanation Answer: B) 20 minutes

Explanation:

Let the total distance to be covered is 84 kms.
Time taken to cover the distance without stoppage = 84/42 hrs = 2 hrs
Time taken to cover the distance with stoppage = 84/28 = 3 hrs.
Thus, he takes 60 minutes to cover the same distance with stoppage.
Therefore, in 1 hour he stops for 20 minutes.

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Q:

The average age of a class is 15.8 years. The average age of the boys in the class is 16.4 years and that of the girls is 15.4 years. What is the ratio of boys to girls in the class ?

A) 1:3 B) 2:3
C) 3:2 D) 3:1
 
Answer & Explanation Answer: B) 2:3

Explanation:

Let number of boys = x  , Let number of girls = y
Total numbers of students = x + y
(x + y) × 15.8 = 16.4x + 15.4y
0.6x = 0.4y
x/y = 0.4/0.6 = 2/3

 

 Ratio of boys and girls in the class is 2:3

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Filed Under: Problems on Ages
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Q:

Read the following information carefully and answer the question below. Seven Students – A, B, C, D, E, F and G like different Pens viz, Reynolds, Cello, Parker, Rotomac, Flair, Linc and Eilcos but not necessarily in the same order. They also study in three different standards viz. 9th, 10th and 12th. Not more than three and not less than two students study in the same class. A do not likes cello pen. Persons who like cello and Flair pens, study in the same class. G studies in 10th standard but he does not likes flair pen. B studies with only one student, who likes linc pens. B does not studies with G. E likes Rotomac but he do not study in class 9. D studies in class 9 but he does not like line pen. A does not study in class 12. F does not like linc pen. The one likes Parker pen, studies in class 10. The one, who likes Reynolds pen, studies in same class with one who likes Flair pen. D likes neither Flair pen nor cello pen.

1. Who likes Parker Pen ?

    (1) F  (2) G  (3) H  (4) None

2. Three of the following four are similar in a certain way. Find the odd one ?

    (1) BE  (2) AD  (3) EG  (4) DF

3. Which three student study in the same class ?

    (1) ADE  (2) DFG  (3) ADF  (4) AEG

4. C likes which pen ?

    (1) Reynolds  (2) Flair  (3) Cello  (4) Linc

Answer

download21486193578.png image


1. Answer (2) G


2. Answer (1) BE All other pairs are in same class.


3. Answer (3) ADF in class 9.


4. Answer (4) Linc pen.

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Q:

At what time between 3 and 4 o’clock will the minute hand and the hour hand are on the same straight line but facing opposite directions ?

A) 3:15 2/8 B) 3:49
C) 3:49 1/11 D) 3:51
 
Answer & Explanation Answer: C) 3:49 1/11

Explanation:

On straight line means 180 degree angle.
180 = 11/2 min – 30 hrs
180 = 11/2 m – 30 × 3
180 = 11/2 m – 90
(180 + 90) 2 = 11 m
m = 540/11 = 49 1/11 minutes.

 

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Filed Under: Clocks
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Q:

At what time between 2 and 3 O'clock, the hands of a clock coincide ?

A) 1 10/11 minutes past 2 B) 1 10/11 minutes past 3
C) 1 11/10 minutes past 3 D) 11 10/11 minutes past 2
 
Answer & Explanation Answer: A) 1 10/11 minutes past 2

Explanation:

Since, in one hour, two hands of a clock coincide only once, so, there will be value.
Required time T = 211H×30 + Ao minutes past H.
Here H - initial position of hour hand = 2 (since 2 O'clock)
A° = Required angle = 0° (Since it coincides)

 

T = 2112×30 + 0o minutes past 2 

 

=> 11011 minutes past 2

 

 

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Filed Under: Clock puzzles
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Q:

In a certain code ARCHIVE is written as DSBGFWJ. How is SYSTEMS is written in that code ?

A) TZTSTUN B) TZTSTNF
C) TZTUTNF D) TZTNTFS
 
Answer & Explanation Answer: B) TZTSTNF

Explanation:

ARC -> CRA ->(+1) DSB
    H ->     H ->(-1) G
IVE  ->  EVI ->(+1) FWJ

 Similarly,

 SYS -> SYS ->(+1) TZT
    T ->     T ->(-1) S
EMS -> SME ->(+1) TNF

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Filed Under: Alphabet Test
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