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Q:

India's first amphibious bus project has been launched by which state government ?

A) Telangana	B) Assam
C) Punjab	D) Gujarat

Answer & Explanation Answer: C) Punjab

Explanation:

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Filed Under: Indian Economy
Exam Prep: CAT
Job Role: Bank PO

Q:

Two trains 85 m and 75 m long are running in same direction with speeds of 62 km/hr and 44 km/hr respectively. In what time will the first train cross the second train ?

A) 22 sec	B) 32 sec
C) 42 sec	D) 52 sec

Answer & Explanation Answer: B) 32 sec

Explanation:

Given that,

1st train speed = 62 km/hr

2nd train speed = 44 km/hr

Hence the relative speed of two trains is : 62-44 = 18 km/hr = $18 \times \frac{5}{18}$ m/s = 5 m/s.

There fore, the first train crosses the second train i.e (85+75)mts of distance with a speed of 5m/s in,

time = $\frac{d i s \tan c e}{s p e e d} = \frac{85 + 75}{5}$ = 32 sec.

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Filed Under: Time and Distance
Exam Prep: CAT
Job Role: Bank Clerk

Q:

An industrial loom weaves 1.14 meters of cloth every second. Approximately, how much time will it take to weave 52 meters of cloth ?

A) 29.32 sec	B) 42.51 sec
C) 39.25 sec	D) 45.61 sec

Answer & Explanation Answer: D) 45.61 sec

Explanation:

Given loom weaves 1.14 mts of cloth in one second then 52 mts of cloth can be weaved by loom in,

1.14 ----- 1

52.0 ------?

$\Rightarrow \frac{52}{1.14}$ = 45.61 sec

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Filed Under: Chain Rule
Exam Prep: CAT
Job Role: Bank PO

Q:

A sales boy is allowed $4 \frac{1}{2}$ % discount on the total sales made by him plus a bonus of $\frac{1}{4}$ % on the sales over Rs.12,000.If his total earnings were Rs.2400, then his total sales(in Rs.) are ?

A) Rs.60,145.23	B) Rs.54,285.54
C) Rs.52,147.85	D) Rs.50,589.47

Answer & Explanation Answer: D) Rs.50,589.47

Explanation:

Let the total earnings be Rs.x

Then $4 \frac{1}{2}$ % of x + $\frac{1}{4}$ % of (x-12000) =2400

$\Rightarrow \frac{9}{2} \times \frac{x}{100} + \frac{1}{4} \times \frac{x - 12000}{100} = 2400$

=> x=50,589.47

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Filed Under: Percentage
Exam Prep: CAT
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Q:

A group consists of 4 couples in which each of the 4 boys have one girl friend.In how many ways they can be arranged in a straight line such that boys and girls occupies alternate positions?

Answer

Answer : 1152

Total positions are 8.

In that boys can be arranged in 4 places and girls can be arranged in 4 places and hence this can be done in 2 ways.

i.e => 4! x 4! x 2 = 24 x 24 x 2=1152.

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Subject: Permutations and Combinations Exam Prep: CAT
Job Role: Bank PO

Q:

The population of a city is 415600.It increased by 25% in the first year and decreased by 30% in the second year.What is the population of the city at the end of second year?

Answer

As per given data, P = 415600, R1= 25% incresed, R2 = 30% decreased

Population of the city at the end of the second year= $p\left ( 1+\frac{R1}{100} \right )\left ( 1-\frac{R2}{100} \right )$

$\Rightarrow$ $415600\left ( 1+\frac{25}{100} \right )\left ( 1-\frac{30}{100} \right )$

$\Rightarrow$ 363650.

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Subject: Percentage Exam Prep: CAT
Job Role: Bank Clerk

Q:

Which one of the following orders presents the correct sequence of the increasing basic nature of the given oxides?

(1) $K_{2} O < N a_{2} O < A l_{2} O_{3} < M g O$

(2) $A l_{2} O_{3} < M g O < N a_{2} O < K_{2} O$

(3) $M g O < K_{2} O < A l_{2} O_{3} < N a_{2} O$

(4) $N a_{2} O < K_{2} O < M g O < A l_{2} O_{3}$

A) Option 1	B) Option 2
C) Option 3	D) Option 4

Answer & Explanation Answer: B) Option 2

Explanation:

While moving from left to right in periodic table basic character of oxide of elements will decrease.

$∴ \to_{I n c r e a \sin g b a s i c s t r e n g t h}^{A l_{2} O_{3} < M g O < N a_{2} O}$

and while descending in the group basic character of corresponding oxides increases.

$∴ \to_{I n c r e a \sin g b a s i c s t r e n g t h}^{N a_{2} O < K_{2} O}$

$∴ C o r r e c t O r d e r i s A l_{2} O_{3} < M g O < N a_{2} O < K_{2} O$

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Filed Under: Chemistry
Exam Prep: AIEEE

Q:

Boron cannot form which one of the following anions?

(1) $B O_{2}^{-}$

(2) $B F_{6}^{3 -}$

(3) $B H_{4}^{-}$

(4) $B (O H)_{4}^{-}$

A) Option 1	B) Option 2
C) Option 3	D) Option 4

Answer & Explanation Answer: B) Option 2

Explanation:

Due to absence of low lying vacant d orbital in B, $s p^{3} d^{2}$ hybridization is not possible hence $B F_{6}^{3 -}$ will not formed.

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Filed Under: Chemistry
Exam Prep: AIEEE

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