eight Search

Q:

Sneha’s weight is 140% of Veena’s weight. Rina’s weight is 90% of Sana’s weight. Sana weighs twice as much as Veena. If Sneha’s weight is x% of Rina’s weight, then x is equal to:

A) 596/9	B) 605/9
C) 645/9	D) 700/9

Answer & Explanation Answer: D) 700/9

Explanation:

Let Veena's weight = 1 kg

Sana's weight = 2 kg

Sneha's weight = 1.4 kg

Rina's weight = 1.8 kg

Now,according to the given data in the question,

$\frac{1.8 x}{100} = 1.4$

x = $\frac{1.4 \times 100}{1.8} = \frac{700}{9} = 77 \frac{7}{9}$ .

Report Error

View Answer Report Error Discuss

Filed Under: Percentage
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Analyst , Bank Clerk , Bank PO , Database Administration , IT Trainer

Q:

How many balls?

Number of balls in the figure...

balls1523099634.jpg image

Answer

You have to actually count all the balls in the pyramid.
Simple way is to count the balls in each level.

So lower most level lets say 1st level has 4 x 4 balls; i.e. 16 balls
Similarly 2nd level has 3 x 3 balls; i.e. 9 balls.
3rd level has 2 x 2 balls; i.e. 4 balls.
The top most level has just 1 ball.

So the total number of balls is 16+9+4+1 = 30.

So the image has 30 Balls in all.

Workspace

Report Error

View answer Workspace Report Error Discuss

Subject: Logic Puzzles Exam Prep: AIEEE , Bank Exams , CAT , GATE , GRE , TOEFL
Job Role: Analyst , Bank Clerk , Bank PO , Database Administration , IT Trainer

Q:

Solve the Riddle?

bana1522056999.jpg image

A) 79 hrs	B) 72 hrs
C) 52 hrs	D) 18 hrs

Answer & Explanation Answer: D) 18 hrs

Explanation:

From the given data,

18 snakes can eat 18 bananas in 18 hrs.

=> 1 snake can eat 1 banana in 18 hrs

=> 79 snakes can eat 79 bananas in 18 hrs.

Hence, 18 hrs.

Report Error

View Answer Report Error Discuss

Filed Under: Math Puzzles
Exam Prep: AIEEE , Bank Exams , CAT , GATE , GRE , TOEFL
Job Role: Analyst , Bank Clerk , Bank PO , Database Administration , IT Trainer

Q:

A ball is thrown vertically upward from the ground. It crosses a point at the height of 25 m twice at an interval of 4 seconds. The ball was thrown with the velocity of

A) 18 m/s	B) 25 m/s
C) 30 m/s	D) 36 m/s

Answer & Explanation Answer: C) 30 m/s

Explanation:

The interval between object pass the same point is 4 sec.

That means in 2 sec, object reaches the top and in next 2 sec, it again reaches the same point.

By the info given, we can find the velocity of that point by using : v=u+(-gt)

0= u - 10×2

u = 20

Then the velocity at 25m is 20m/sec.

so the initial velocity is

$- v^{2} = u^{2} + (- 2 gh) 400 = u^{2} - 2 x 10 x 25 u^{2} = 900 = > u = 30 m / s$

Report Error

View Answer Report Error Discuss

Filed Under: Physics
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Analyst , Bank Clerk , Bank PO , IT Trainer

Q:

Solve if you are Genius?

27973011_1559273064179792_7533515893130149894_n1519041289.jpg image

A) 36	B) 42
C) 48	D) 54

Answer & Explanation Answer: D) 54

Explanation:

Here the given Number Puzzle follows a pattern that, Sum of the numbers on the corners on the two squares is same and is equal to 54.

i.e,

13 + 15 + 14 + 12 = 54

and

8 + 22 + 9 + 15 = 54

Report Error

View Answer Report Error Discuss

Filed Under: Number Puzzles
Exam Prep: GATE , CAT , Bank Exams , AIEEE
Job Role: IT Trainer , Database Administration , Bank PO , Bank Clerk , Analyst

Q:

The average weight of 45 passengers in a bus is 52 kg. 5 of them whose average weight is 48 kg leave the bus and other 5 passengers whose average weight is 54 kg join the bus at the same stop. What is the new average weight of the bus?

A) 54.21 kgs	B) 51.07 kgs
C) 52.66 kgs	D) 53.45 kgs

Answer & Explanation Answer: C) 52.66 kgs

Explanation:

Given total number of passengers in the bus = 45

First average weight of 45 passengers = 52 kgs

Average weight of 5 passengers who leave bus = 48

Average weight of 5 passengers who joined the bus = 54

Therefore, the net average weight of the bus is given by

$= \frac{45 x 52 - (5 x 48) + (5 x 54)}{45} = \frac{2370}{45} = \frac{158}{3} = 52.66 kgs .$

Report Error

View Answer Report Error Discuss

Filed Under: Average
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Analyst , Bank Clerk , Bank PO , Database Administration , IT Trainer

Q:

An alloy of copper and bronze weight 50g. It contains 80% Copper. How much copper should be added to the alloy so that percentage of copper is increased to 90%?

A) 45 gm	B) 50 gm
C) 55 gm	D) 60 gm

Answer & Explanation Answer: B) 50 gm

Explanation:

Initial quantity of copper = $\frac{80}{100} x 50$ = 40 g

And that of Bronze = 50 - 40 = 10 g

Let 'p' gm of copper is added to the mixture

=> $(50 + p) x \frac{90}{100}$ = 40 + p

=> 45 + 0.9p = 40 + p

=> p = 50 g

Hence, 50 gms of copper is added to the mixture, so that the copper is increased to 90%.

Report Error

View Answer Report Error Discuss

Filed Under: Alligation or Mixture
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Analyst , Bank Clerk , Bank PO

Q:

Find the Missing Number Puzzle for the Given

number011517998001.jpg image

A) 8	B) 16
C) 9	D) 12

Answer & Explanation Answer: C) 9

Explanation:

Given

6 = 3 => Number of letters in SIX = 3

12 = 6 => Number of letters in TWELVE = 6

14 = 8 => Number of letters in FOURTEEN = 8

Similarly,

22 = 9 => Number of letters in TWENTY TWO = 9

Therefore, 22 = 9.

Report Error

View Answer Report Error Discuss

Filed Under: Number Puzzles
Exam Prep: TOEFL , GRE , GATE , CAT , Bank Exams , AIEEE
Job Role: IT Trainer , Database Administration , Bank PO , Bank Clerk , Analyst

Searching for "eight"

Quick Links