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Q:

In the following question, various terms of an alphanumerical series are given with one or more terms missing as shown by (?). Choose the missing terms out of the given alternatives. Q1F, S2E, U6D, W21C, ?

A) Z88B	B) Y88B
C) Y44B	D) K25P

Answer & Explanation Answer: B) Y88B

Explanation:

The first letter moves two steps forward. The last letter moves one steps backward. The number series runs as follows :
1 x 1 + 1 = 2
2 x 2 + 2 = 6
6 x 3 + 3 = 21
21 x 4 + 4 = 88.

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Q:

In the following question, various terms of an alphanumerical series are given with one or more terms missing as shown by (?). Choose the missing terms out of the given alternatives. D-4, F-6, H-8, J-10, ?, ?

A) L-12,N-14	B) K-12, M-14
C) K-14, M-14	D) K-12, M-14

Answer & Explanation Answer: A) L-12,N-14

Explanation:

The letters are alternate and the numbers indicate their position in the alphabet from the beginning.

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Q:

In the following question, various terms of an alphanumerical series are given with one or more terms missing as shown by (?). Choose the missing terms out of the given alternatives. P3C, R5F, T8I, V12L, ?

A) X17M	B) X16O
C) X17O	D) Y17O

Answer & Explanation Answer: C) X17O

Explanation:

The first letters of the terms are alternate.
The sequence followed by the numbers is +2, +3, +4,....
The last letter of is three steps ahead of the last letter of the preceding term.

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Filed Under: Number Series

Q:

A man sitting in a train which is traveling at 50 kmph observes that a goods train, traveling in opposite direction, takes 9 seconds to pass him. If the goods train is 280 m long, find its speed.?

A) 60	B) 62
C) 64	D) 65

Answer & Explanation Answer: B) 62

Explanation:

Relative speed =280/9 m / sec = (280/9*18/5) kmph = 112 kmph.

Speed of goods train = (112 - 50) kmph = 62 kmph.

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Filed Under: Problems on Trains

Q:

In the following question, various terms of an alphanumerical series are given with one or more terms missing as shown by (?). Choose the missing terms out of the given alternatives. A/2, B/4, C/6, D/8, ?, ?

A) D/10, E/10	B) E/10, F/12
C) E/8, F/10	D) E/12, F/14

Answer & Explanation Answer: B) E/10, F/12

Explanation:

The letters are in alphabetical order. The numbers increase by two.

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Filed Under: Number Series

Q:

Two trains having equal lengths, take 10 seconds and 15 seconds respectively to cross a post. If the length of each train is 120 meters, in what time (in seconds) will they cross each other when traveling in opposite direction?

A) 10	B) 25
C) 12	D) 20

Answer & Explanation Answer: C) 12

Explanation:

Speed of train 1 = $(\frac{120}{10}) m / s e c$ = 12 m/sec

Speed of train 2 = $(\frac{120}{15}) m / s e c$ = 8 m/sec

if they travel in opposite direction, relative speed = 12 + 8 = 20 m/sec

distance covered = 120 + 120 = 240 m

time = distance/speed = 240/20 = 12 sec

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Filed Under: Problems on Trains

Q:

A train is traveling at 48 kmph . It crosses another train having half of its length , traveling in opposite direction at 42 kmph, in 12 seconds. It also passes a railway platform in 45 seconds. What is the length of the platform ?

A) 500	B) 400
C) 360	D) 480

Answer & Explanation Answer: B) 400

Explanation:

Speed of train 1 = 48 kmph
Let the length of train 1 = 2x meter

Speed of train 2 = 42 kmph
Length of train 2 = x meter (because it is half of train 1's length)

Distance = 2x + x = 3x
Relative speed= 48+42 = 90 kmph = (90*5/18) m/s = 25 m/s

Time = 12 s

Distance/time = speed

=>3x/12 = 25 $\Rightarrow$ (25*12)/3

Length of the first train = 2x = 200 meter
Time taken to cross the platform= 45 s

Speed of train 1 = 48 kmph = 480/36 = 40/3 m/s

Distance = 200 + y [where y is the length of the platform]

x =100m => 200+y = 45* 40/3
$\Rightarrow$ y = 400m

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Filed Under: Problems on Trains

Q:

Two stations P and Q are 110 km apart on a straight track. One train starts from P at 7 a.m. and travels towards Q at 20 kmph. Another train starts from Q at 8 a.m. and travels towards P at a speed of 25 kmph. At what time will they meet?

A) 10.30	B) 10
C) 8.45	D) 9.30

Answer & Explanation Answer: B) 10

Explanation:

Assume both trains meet after x hours after 7 am

Distance covered by train starting from P in x hours = 20x km

Distance covered by train starting from Q in (x-1) hours = 25(x-1)

Total distance = 110

=> 20x + 25(x-1) = 110

=> 45x = 135

=> x= 3

Means, they meet after 3 hours after 7 am, ie, they meet at 10 am

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Filed Under: Problems on Trains

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