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Q:

The diagonal of a rectangle is $\sqrt{41}$ cm and its area is 20 sq. cm. The perimeter of the rectangle must be:

A) 18	B) 28
C) 38	D) 48

Answer & Explanation Answer: A) 18

Explanation:

$\sqrt{(l^{2} + b^{2})} = \sqrt{41}$ (or) $l^{2} + b^{2} = 41$

Also, $l b = 20$

${(l + b)}^{2} = l^{2 +} b^{2} + 2 l b$ = 41 + 40 = 81

(l + b) = 9.

Perimeter = 2(l + b) = 18 cm.

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Q:

A man walked diagonally across a square lot. Approximately, what was the percent saved by not walking along the edges?

A) 30	B) 40
C) 50	D) 60

Answer & Explanation Answer: A) 30

Explanation:

Let the side of the square(ABCD) be x meters.

Then, AB + BC = 2x metres.

AC = $\sqrt{2 x}$ = (1.41x) m.

Saving on 2x metres = (0.59x) m.

Saving % = $\frac{0.59 x}{2 x} * 100$ = 30% (approx)

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Q:

The diagonal of the floor of a rectangular closet is 7 $\frac{1}{2}$ feet. The shorter side of the closet is 4 $\frac{1}{2}$ feet. What is the area of the closet in square feet?

A) 9	B) 18
C) 27	D) 36

Answer & Explanation Answer: C) 27

Explanation:

Other side = $\sqrt{d^{2} - s^{2}}$ = $\sqrt{(\frac{225}{4} - \frac{81}{4})}$ = $\sqrt{\frac{144}{4}}$ = 6 ft

Area of closet = (6 x 4.5) sq. ft = 27 sq. ft.

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Q:

A rectangular park 60 m long and 40 m wide has two concrete crossroads running in the middle of the park and rest of the park has been used as a lawn. If the area of the lawn is 2109 sq. m, then what is the width of the road?

A) 1	B) 2
C) 3	D) 4

Answer & Explanation Answer: C) 3

Explanation:

Area of the park = (60 x 40) = 2400 $m^{2}$

Area of the lawn = 2109 $m^{2}$

Area of the crossroads = (2400 - 2109) = 291 $m^{2}$

Let the width of the road be x metres. Then,

$60 x + 40 x - X^{2} = 291$

$x^{2} - 100 x + 291 = 0$

(x - 97)(x - 3) = 0
x = 3.

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Q:

The ratio between the perimeter and the breadth of a rectangle is 5 : 1. If the area of the rectangle is 216 sq. cm, what is the length of the rectangle?

A) 16	B) 18
C) 20	D) 22

Answer & Explanation Answer: B) 18

Explanation:

$\frac{2 (l + b)}{b} = \frac{5}{1}$ => 2l + 2b = 5b => 3b = 2l

b=(2/3)l

Then, Area = 216 cm²

=> l x b = 216 => l x (2/3)l =216

l = 18 cm.

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Q:

An error 2% in excess is made while measuring the side of a square. The percentage of error in the calculated area of the square is:

A) 1.04	B) 2.04
C) 3.04	D) 4.04

Answer & Explanation Answer: D) 4.04

Explanation:

100 cm is read as 102 cm.

A1 = (100*100)Sq.cm

A2 = (102*102)Sq.cm

(A2 - A1) = $102^{2} - 100^{2}$ = (102 + 100) x (102 - 100) = 404 sq.cm.

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Q:

The ratio between the length and the breadth of a rectangular park is 3 : 2. If a man cycling along the boundary of the park at the speed of 12 km/hr completes one round in 8 minutes, then the area of the park (in sq. m) is:

A) 153600	B) 143600
C) 13600	D) 16300

Answer & Explanation Answer: A) 153600

Explanation:

Let length = 3x metres and breadth = 2x metres.

Then, 2(3x + 2x) = 1600 or x = 160.

Length = 480 m and Breadth = 320 m.Area = (480 x 320) sq.m = 153600 sq.m

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Q:

12 people at a party shake hands once with everyone else in the room.How many handshakes took place?

A) 72	B) 66
C) 76	D) 64

Answer & Explanation Answer: B) 66

Explanation:

There are 12 people, so this is our n value.

So, $12 C_{2}$ 1= 66

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