India’s space agency on Feb 15th, 2017 launched a record 104 satellites from a single rocket as it crossed another milestone in its low-cost space-exploration program. The satellites from seven countries were carried by the Indian Space Research Organization’s Polar Satellite Launch Vehicle on its 38th consecutive successful flight. On board was a 714kg satellite for earth observation and more than 100 smaller satellites weighing less than 10kg each. Three were Indian-owned, 96 were from US companies, and the rest belonged to companies based in Israel, Kazakhstan, the Netherlands, Switzerland and the United Arab Emirates. Most were owned by Planet Labs Inc, a US-based Earth-imaging company. 

Here, S = {1, 2, 3, 4, ...., 19, 20}=> n(s) = 20
Let E = event of getting a multiple of 4 or 15
=multiples od 4 are {4, 8, 12, 16, 20}
And multiples of 15 means multiples of 3 and 5
= {3, 6 , 9, 12, 15, 18, 5, 10, 15, 20}.
= the common multiple is only (15).
=> E = n(E)= 6
Required Probability = P(E) = n(E)/n(S) = 6/20 = 3/10.

Given the company has 8 SD + 6 SRP + 7 IN = 21 cars + 'x' small cars.
Given SD makes 1/4 th of the total fleet.
=> 8 = 1/4 (21 + x)
=> 32 = 21 + x
=> x = 11
Therefore, the company has 11 small cars.

Let the number of males be 'M'
Let the number of females be 'F'
From the given conditions,
(F-15)=2M.....(i)
F=5(M-45).....(ii)
By solving the equations (1) & (2) we get M = 80
Then substitute M = 80 in (1)
F = 2M + 15
F = 2 x 80 + 15
=> F = 175
Therefore, number of males = 80 and females = 175 in the party.

PSRQ --> {16, 19, 18, 17} - next 3 alphabets of "P" is written in reverse order
SVUT --> {19, 22, 21, 20} - next 3 alphabets of "S" is written in reverse order

MNPO --> {13, 14, 16, 15}

KNML --> {11, 14, 13, 12} - next 3 alphabets of "K" is written in reverse order

Except "MNPO", others are not in consecutive order.

Let CP = 100,
42 % increase => SP = 142
10 % discount in SP => ((142 x 10)/100) = 14.2
So 1st SP = (142 - 14.2) = 127.8, again 12 % discount in 1st SP ((127.8 x 11)/100) = 14.058
2nd SP = (127.8 - 14.058) = 113.742,
So finally CP = 100, SP = 113.742, => gain = 13.742%.

Let the speed of goods truck be 'p' kmph
Distance covered by goods truck in 10hrs (4+6) = Distance covered by other truck in 4 hrs.
10p = 4 x 90
p = 36kmph.
Therefore, the speed of the goods truck is p = 36 kmph.