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Q:

Sum of the ages of Rajesh, Suresh, Mahesh and Dinesh is 76 years. 7 years hence, their age ratio is 7:6:5:8. Find Mahesh’s present age ?

A) 17 years	B) 13 years
C) 14 years	D) 16 years

Answer & Explanation Answer: B) 13 years

Explanation:

Given R + S + M + D = 76

=> R+7 : S+7 : M+7 : D+7 = 7:6:5:8

=> Let the ratio = x

=> M+7 = 5x

=> M = 5x-7

=> R = 7x-7

=> S = 6x-7

=> D = 8x-7

=> R + S + M + D = 76

=> 7x-7 + 6x-7 + 5x-7 + 8x-7 = 76

=> 26x - 28 = 76

=> 26x = 104

=> x = 4

=> Mahesh's present age = 5x-7 = 20 - 7 = 13 years.

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Filed Under: Problems on Ages
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Q:

P alone can do a piece of work in 24 days. The time taken by P to complete one-third of work is equal to time taken by Q to complete half of the work. How many days are required to complete by P and Q working together ?

A) 9 3/5 days	B) 7 days
C) 6 3/7 days	D) 8 days

Answer & Explanation Answer: A) 9 3/5 days

Explanation:

Let the total work be 'W'

As per the given information,

P can complete the work 'W' in 24 days.

=> one day work of P = W/24

And also given that,

The time taken by P to complete one-third of work is equal to time taken by Q to complete half of the work

=> PW/3 = QW/2

=> P's

1 day = W/24

? = W/3

=> ? = 24W/3W = 8

=> QW/2 = 8 days

=> Q alone can complete the work W in 16 days

=> P + Q can complete the work in

1/24 + 1/16 = 5/48

=> 48/5 days = 9 3/5 days.

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Filed Under: Time and Work
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Q:

Find the missing number in the following Series ?

18, 97, 26, 91, ? , 83

A) 32	B) 36
C) 30	D) 34

Answer & Explanation Answer: D) 34

Explanation:

The given series follows the pattern that,

18, 97, 26, 91, ?, 83

=> 18 + 8 = 26

=> 97 - 8 = 91

=> 26 + 8 = 34

=> 91 - 8 = 83

Hence, the missing number is 34.

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Filed Under: Odd Man Out
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Q:

Three friends Rudra, Siva and Anvesh start to run around a circular stadium. They complete a revolution in 24, 36 and 30 seconds respectively. After how many minutes will they meet at the starting point ?

A) 60	B) 120
C) 360	D) 6

Answer & Explanation Answer: D) 6

Explanation:

For this we have to find the LCM of 24, 36 and 30

LCM of 24, 36 and 30 = 360 sec

360/60 min = 6 minutes.

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Filed Under: Time and Distance
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Q:

In a competitive exam, the number of passed students was four times the number of failed students. If there had been 35 fewer appeared students and 9 more had failed, the ratio of passed and failed students would have been 2 : 1, then the total number of students appered for the exam ?

A) 175	B) 165
C) 155	D) 145

Answer & Explanation Answer: C) 155

Explanation:

Let the number of failed students be x

=> Number of passed students = 4x

So total number of students was 5x

From the given data,

If total number of students be 5x – 35

=> 4x-35-9/x+9 = 2/1

=> 4x – 44 = 2(x + 9)

=> 4x – 2x = 18 + 44

=> x = 31

Total number = 31×5

= 155

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Filed Under: Ratios and Proportions
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Q:

When a women sells 20 articles for Rs. 160, there is 40% loss. How many articles should she sell for Rs. 240 in order to earn 20% profit ?

A) 16	B) 15
C) 17	D) 14

Answer & Explanation Answer: B) 15

Explanation:

Given when she sells at Rs. 160 for 20 articles, she get 40% loss.

Then, to get 20% profit selling at Rs. 240 for let 'P' articles

=> $\frac{\frac{160}{20}}{60} = \frac{\frac{240}{p}}{120}$

=> 120 x 160 x P = 20 x 70 x 240

=> P = 15 articles.

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Filed Under: Profit and Loss
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Q:

Who has been appointed as the deputy director-general of World Health Organization (WHO) ?

A) Dr. Soumya Swaminathan	B) Rajat Nandan
C) prof. Dr. Vikash Jha	D) Sunil Narayan

Answer & Explanation Answer: A) Dr. Soumya Swaminathan

Explanation:

The World Health Organization is a specialized agency of the United Nations that is concerned with international public health. It was established on 7 April 1948, Headquartered in Geneva, Switzerland.

Dr Soumya Swaminathan has been appointed the deputy director general for programmes (DDP) of World Health Organisation (WHO). She also holds a key position as secretary in the department of health research, ministry of health and family welfare.

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Filed Under: World Organisations
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Q:

P can do a piece of work in 5 less days than Q. If both of them can do the same work in $11 \frac{1}{9}$ days, in how many days will Q alone do the same work ?

A) 24 days	B) 25 days
C) 20 days	D) 19 days

Answer & Explanation Answer: B) 25 days

Explanation:

Let Q complete that work in 'L' days

=> $\frac{1}{L} + \frac{1}{L - 5} = \frac{9}{100}$

=> $9 L^{2} - 245 L + 500 = 0$

L = 25 days.

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Filed Under: Time and Work
Exam Prep: GATE , CAT , Bank Exams , AIEEE
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