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Q:

The average age of 80 boys in a class is 15. The average age of group of 15 boys in the class is 16 and the average of another 25 boys in the class is 14. What is the average age of the remaining boys in the class ?

A) 12.24 yrs B) 13.25 yrs
C) 16 yrs D) 15.25 yrs
 
Answer & Explanation Answer: D) 15.25 yrs

Explanation:

Total ages of 80 boys = 15 x 80 = 1200 yrs.
Total age of 16 boys = 15 x 16 = 240 yrs
Total age of 25 boys = 14 x 25 = 350 yrs.
Average age of remaining boys = 1200 - (240+350) / 80 - (25+15) = 610/41 = 15.25 yrs.

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Filed Under: Problems on Ages
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Q:

Each consonant in the word TIRADES is replaced by the previous letter in the English alphabet and each vowel is replaced by the next letter in the English alphabet and the new letters are arranged alphabetically. Which of the following will be the fourth from the right end ?

A) S B) Q
C) J D) U
 
Answer & Explanation Answer: C) J

Explanation:

Given word is TIRADES
Now the consonants T, R, D, S are replaced by S, Q, C, R
And Vowels are I, A, E are replaced by J, B and F
They are arranged alphabetically
New word is BCFJQRS

The fourth letter from the right end is J.

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Filed Under: Alphabet Test
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Q:

When all the students in a school are made to stand in rows of 54, 30 such rows are formed. If the students are made to stand in rows of 45, how many such rows will be formed ?

A) 22 B) 36
C) 32 D) 26
 
Answer & Explanation Answer: B) 36

Explanation:

Total number of students = 54 x 30
When arranged in rows of 45, number of rows formed are,
54x3045 = 36.

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Q:

There are two numbers such that the sum of twice the first number and thrice the second number is 100 and sum of thrice the first number and twice the second number is 120. Which is the larger number ?

A) 32 B) 24
C) 26 D) 38
 
Answer & Explanation Answer: A) 32

Explanation:

Let the first number be K and second number be L
Then, 2K + 3L = 100.....(1)
3K + 2L = 120.......(2)
solving (1)&(2), we get
K = 32 and L = 12

Hence the largest number is 32.

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Filed Under: Numbers
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Q:

Sonika invested an amount of Rs.5800 for 2 years. At what rate of compound interest will she get an amount of Rs.594.50 at the end of 2 years ?

A) 6.5% B) 6%
C) 5% D) 4.5%
 
Answer & Explanation Answer: C) 5%

Explanation:

C.I = P1+r100t-1

 

594.5 = 58001+r1002-1

 594.55800+1=1+r1002

 

r100=1.05-1=0.05=> r = 5 % .

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Filed Under: Compound Interest
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Q:

If the numerator of a fraction is increased by 150% and the denominator of the fraction is increased by 350%, the resultant fraction is 25/51. What is the original fraction ?

A) 31/25 B) 15/17
C) 14/25 D) 11/16
 
Answer & Explanation Answer: B) 15/17

Explanation:

The original fraction is  2551 × 350+100150+100  = 15/17.

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Q:

From the given series of numbers, if half of the second highest number is subtracted from the third highest number, what will be the value ?

519 328 746 495 837

A) 146 B) 203
C) 345 D) 96
 
Answer & Explanation Answer: A) 146

Explanation:

From the given series of numbers, if half of the second highest number is subtracted from the third highest number, what will be the value ?

Now arranging the given numbers in descending order.
837 746 519 495 328

519 - 746/2 = 519 - 373 = 146.

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Q:

In a year, Holi was enjoyed on 6th March 9 AM and Deepawali was celebrated on 11th November 8 PM. The total time interval (in hours) between the two was ?

A) 2101 hrs B) 4125 hrs
C) 5124 hrs D) 6011 hrs
 
Answer & Explanation Answer: D) 6011 hrs

Explanation:

From March 6th to November 11th,
there are 250 days and
Thus 250 x 24 hours
So from Mar 6th 9AM to Nov 11th 8PM, there will be 250 x 24 + 11 hours = 6011 hrs.

 

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