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Q:

Count the number of triangles and squares in the given figure.

A) 36 triangles, 7 Squares B) 38 triangles, 9 Squares
C) 40 triangles, 7 Squares D) 42 triangles, 9 Squares
 
Answer & Explanation Answer: C) 40 triangles, 7 Squares

Explanation:

The figure may be labelled as shown 

 

 

Triangles :

 


The Simplest triangles are BGM, GHM, HAM, ABM, GIN, IJN, JHN, HGN, IKO, KLO, LJO, JIO, KDP, DEP, ELP, LKP, BCD and AFE i.e 18 in number

 

The triangles composed of two components each are ABG, BGH, GHA, HAB, HGI, GIJ, IJH, JHG, JIK, IKL, KLJ,LJI, LKD, KDE, DEL and ELK i.e 16 in number.

 

The triangles composed of four components each are BHI, GJK, ILD, AGJ, HIL and JKE i.e 6 in number.

 

Total number of triangles in the figure = 18 + 16 + 6 =40.

 

Squares :

 


The Squares composed of two components each are MGNH, NIOJ, and OKPL i.e 3 in number

 

The Squares composed of four components each are BGHA, GIJH, IKJL and KDEL i.e 4 in number

 

Total number of squares in the figure = 3 + 4 =7

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Q:

Find the number of triangles in the given figure?

A) 10 B) 12
C) 14 D) 16
 
Answer & Explanation Answer: C) 14

Explanation:

The figure may be labelled as shown

The simplest triangles are ABJ, ACJ, BDH, DHF, CIE and GIE i.e 6 in number.

The triangles composed of two components each are ABC, BDF, CEG, BHJ, JHK, JKI and CJI i.e 7 in number.

There is only one triangle JHI which is composed of four components.

Thus, there are 6 + 7 + 1 = 14 triangles in the given figure.

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Q:

Find the number of triangles in the given figure?

A) 11 B) 13
C) 15 D) 17
 
Answer & Explanation Answer: C) 15

Explanation:

We may label the figure as shown.

The Simplest triangles are AFB, FEB, EBC, DEC, DFB and AFD i.e 6 in number.

The triangles composed of two components each are AEB, FBC, DFC, ADE, DBE and ABD i.e 6 in number.

The triangles composed of three components each are ADC and ABC i.e 2 in number.

There is only one triangle i.e DBC which is composed of four components.

Thus, there are 6 + 6 + 2 + 1 = 15 triangles in the figure

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Q:

What is the number of rectangles in the following figure?

A) 6 B) 7
C) 9 D) 11
 
Answer & Explanation Answer: C) 9

Explanation:

The simplest rectangles are AEHG, EFJH, FBKJ, JKCL and GILD i.e 5 in number.

The rectangles composed of two components each are AFJG and FBCL i.e 2 in number

Only one rectangle namely AFLD is composed of three components and only one rectangle namely ABCD is composed of five components.

Thus, there are 5 + 2 + 1 + 1 = 9 rectangles in the given figure.

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Q:

Using numbers from 0 to 9 the number of 5 digit telephone numbers that can be formed is

A) 1,00,000 B) 59,049
C) 3439 D) 6561
 
Answer & Explanation Answer: C) 3439

Explanation:

The numbers 0,1,2,3,4,5,6,7,8,9 are 10 in number while preparing telephone numbers any number can be used any number of times.

 

This can be done in 105ways, but '0' is there

 

So, the numbers starting with '0' are to be excluded is 94 numbers.

 

 Total 5 digit telephone numbers = 105- 94 = 3439

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Q:

The number of ways that 8 beads of different colours be strung as a necklace is 

A) 2520 B) 2880
C) 4320 D) 5040
 
Answer & Explanation Answer: A) 2520

Explanation:

The number of ways of arranging n beads in a necklace is (n-1)!2=(8-1)!2=7!2 = 2520 

(since n = 8)

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Q:

The number of ways that 7 teachers and 6 students can sit around a table so that no two students are together is 

A) 7! x 7! B) 7! x 6!
C) 6! x 6! D) 7! x 5!
 
Answer & Explanation Answer: B) 7! x 6!

Explanation:

The students should sit in between two teachers. There are 7 gaps in between teachers when they sit in a roundtable. This can be done in 7P6ways. 7 teachers can sit in (7-1)! ways.

 

 Required no.of ways is = 7P6.6! = 7!.6!

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Q:

If A1, A2, A3, A4, ..... A10 are speakers for a meeting and A1 always speaks after, A2 then the number of ways they can speak in the meeting is 

A) 9! B) 9!/2
C) 10! D) 10!/2
 
Answer & Explanation Answer: D) 10!/2

Explanation:

As A1 speaks always after A2, they can speak only in  1st  to 9th places and 

 

A2 can speak in 2nd to 10 the places only when A1 speaks in 1st place 

 

A2 can speak in 9 places the remaining 

 

 A3, A4, A5,...A10  has no restriction. So, they can speak in 9.8! ways. i.e

 

when A2 speaks in the first place, the number of ways they can speak is 9.8!.

 

When A2 speaks in second place, the number of ways they can speak is  8.8!.

 

When A2 speaks in third place, the number of ways they can speak is  7.8!. When A2 speaks in the ninth place, the number of ways they can speak is 1.8!

 

 

 

Therefore,Total Number of ways they can  speak = (9+8+7+6+5+4+3+2+1) 8! = 92(9+1)8! = 10!/2

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