A stub network has only one default path to non-local hosts and no outside network knowledge. Non-local stub network traffic uses a single logical path when traveling in and out of the network.

Stub networks are essentially local area networks (LAN) that either do not connect to the outside and relay data packets internally or are dead-end LANs that know of only one network exit. Stub networks may have multiple connections but use one path to single points of destination.

Hence, a stub network is a network that has only one entry and exit point.

The IUPAC nomenclature in organic chemistry is a systematic method that is used to name organic chemical compounds as recommended by the International Union of Pure and Applied Chemistry (IUPAC).

The IUPAC name of the given complex [Co (NH₃)₄Cl₂ ]Cl is - Tetra-ammine dichloro cobalt (III) chloride.

The complex [Co (NH₃)₄ Cl₂ ] Cl ionizes an aqueous solution to furnish the chloride ion Cl⁻ and [Co (NH₃)₄ Cl₂ ] ⁺.

All of the genetic information in a cell was initially thought to be confined to the DNA in the chromosomes of the cell nucleus.

It is now known that small circular chromosomes, called extranuclear, or cytoplasmic, DNA, are located in two types of organelles found in the cytoplasm of the cell.

These organelles are the mitochondria in animal and plant cells and the chloroplasts in plant cells.

Chloroplast DNA (cpDNA) contains genes that are involved with aspects of photosynthesis and with components of the special protein-synthesizing apparatus that is active within the organelle.

Mitochondrial DNA (mtDNA) contains some of the genes that participate in the conversion of the energy of chemical bonds into the energy currency of the cell—a chemical called adenosine triphosphate (ATP)—as well as genes for mitochondrial protein synthesis.

The sentence which contains both an adverb and a conjunction is "Adam crept silently up the stairs, but couldn't slow his heartbeat."

Here, Adverb - Silently and Conjunction - But.

The given expression can be simplified as

6 ÷ 2 (1 + 2)

The expression can be simplified further by the order of operations, using BODMAS rule.

First evaluate Parentheses/Brackets, then evaluate Exponents/Orders, then evaluate Multiplication-Division, and finally evaluate Addition-Subtraction.

Now, the expression becomes 6 ÷ 2 (3)

According to the order of operations, division and multiplication have the same precedence, so the correct order is to evaluate from left to right. First take 6 and divide it by 2, and then multiply by 3.

6 ÷ 2 × 3

= 3 × 3

= 9

But not  6÷2×3 = 6 ÷ 6 = 1

Hence, 6 ÷ 2 (1 + 2) = 9.

A pure solid and a pure liquid are definitely a single phase because they are so united, or homogeneous. This leads to a homogeneous mixture also being a single phase.

Hence, the option that cannot be considered a single phase is A. a heterogeneous mixture.

Using BODMAS law,

3 x 3 + 3 - 3 + 3 =

3 x 3 = 12

= 12 + 3 - 3 + 3

=  9 + 3

= 12

Hence, 3 x 3 + 3 - 3 + 3 = 12.