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Q:

A fraction becomes 2/3 when 1 is added to both, its numerator and denominator .And , it becomes 1/2 when 1 is subtracted from both the numerator and denominator. What is the fraction?

Answer

Let required fraction be $\frac{x}{y}$ then

$\frac{x+1}{y+1}=\frac{2}{3}\Rightarrow 3x-2y=-1$ ............. (i)

and $\frac{x-1}{y-1}=\frac{1}{2}\Rightarrow 2x-y=1$ ............ (ii)

Solving (i) and (ii) we get x=3, y=5

$\inline \therefore$ Required fraction = $\frac{3}{5}$

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Subject: Problems on Numbers

Q:

Simplify the following equation.

$\frac{19}{43} + \frac{1}{(2 + \frac{1}{3 + \frac{1}{1 + \frac{1}{4}}})}$

A) 43/19	B) 1
C) 38/19	D) None of these

Answer & Explanation Answer: D) None of these

Explanation:

After solving we get,

62/931.

None of the options satisfy.

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Q:

The age of a man is 4 times of his son. Five years ago, the man was nine times old as his son was at that time. The present age of man is?

Answer

Let the son's age be x years and the father's age be 4x years

$\Rightarrow (4x-5)=9(x-5)$

5x = 40

x = 8

$\inline \therefore$ present age of the father = $\inline 4x$ = $\inline 4\times 8$ = 32 years

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Subject: Problems on Ages

Q:

The average age of a group of 10 students is 15 years. When 5 more students join the group, the average age increase by 1 year. The average age of the new students is?

Answer

Total age of 10 students = 150 years

Total age of 15 students = 240 years

Total age of 5 new students = 240 - 150 = 90 years

$\inline \therefore$ Average age of 5 new students = $\frac{90}{5}$ = 18 years

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Subject: Problems on Ages

Q:

The Average age of 12 men is decreased by one year when two of them having ages 28 years and 32 years are replaced by two women of same age . The age of a women is?

Answer

Suppose age of each women be W and average age of 12 men be x

$\therefore \frac{12x-28-32+2W}{12}=x-1$

$\therefore W=24$

Hence , each woman's age = 24 years

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Subject: Problems on Ages

Q:

8 years ago Rama's mother was five times older than her daughter. After 8 years the mother will be twice older than her daughter . Find the present age of Rama?

Answer

Let Rama's age 8 years ago be x years and mother's age 8 years ago be 5x

$\Rightarrow 2(x+16)= 5x+16$

$2x+32=5x+16$

$3x=16$

$x=\frac{16}{3}$ years

Hence, present age of Rama = $x+8=\frac{16}{3}+8=\frac{40}{3}=13\frac{1}{3}$ years

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Subject: Problems on Ages

Q:

The average of ages of threee persons is 60 years . Those ages are in the proportion of 1:2:3. what is the age of the youngest one among them?

Answer

Suppose the ages of three persons are x, 2x, 3x years respectively

$\Rightarrow \frac{x+2x+3x}{3}=60$

$\Rightarrow 6x=180$

$\Rightarrow x=30$

Hence, age of youngest person = x = 30 years.

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Subject: Problems on Ages

Q:

The Age of Ashok , Deepak and Ramu are in the proportion of 3:5:6. If the difference between the ages of Deepak and Ramu is 5 years . what is Ashok's age in years?

Answer

Suppose the ages of Ashok, Deepak and Ramu are 3x, 5x and 6x years respectively.

$6x-5x=5\: \: \Rightarrow x=5$

Hence , Ashok's age = $3x$ = $3\times 5$ = 15 years

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Subject: Problems on Ages

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