Searching for "he"

Q:

Find the odd man out.

41, 43, 47, 53, 61, 71, 73, 81

A) 41 B) 61
C) 71 D) 81
 
Answer & Explanation Answer: D) 81

Explanation:

Each of the numbers except 81 is a prime number.

Report Error

View Answer Report Error Discuss

Filed Under: Odd Man Out

Q:

Find the odd man out.

2, 5, 10, 17, 26, 37, 50, 64

A) 50 B) 37
C) 26 D) 64
 
Answer & Explanation Answer: D) 64

Explanation:

(1*1)+1 , (2*2)+1 , (3*3)+1 , (4*4)+1 , (5*5)+1 , (6*6)+1 , (7*7)+1 , (8*8)+1

But, 64 is out of pattern.

Report Error

View Answer Report Error Discuss

Filed Under: Odd Man Out

Q:

Find the odd man out?

396, 462, 572, 427, 671, 264.

A) 671 B) 462
C) 427 D) 264
 
Answer & Explanation Answer: C) 427

Explanation:

Here the given series is 396, 462, 572, 427, 671, 264.

In all the terms, the middle digit is the sum of first and third digit except 427.

 

So the Odd number in the given series is 427.

Report Error

View Answer Report Error Discuss

Filed Under: Odd Man Out
Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Analyst , Bank Clerk , Bank PO

Q:

A wheel that has 6 cogs is meshed with a larger wheel of 14 cogs. When the smaller wheel has made 21 revolutions, then the number of revolutions mad by the larger wheel is:

A) 4 B) 9
C) 12 D) 49
 
Answer & Explanation Answer: B) 9

Explanation:

Let the required number of revolutions made by larger wheel be x.

 

Then, More cogs, Less revolutions (Indirect Proportion)

 

  14 : 6 :: 21 : x => 14 x x = 6 x 21

 

x=6*21/14  =>  x=9

Report Error

View Answer Report Error Discuss

Filed Under: Chain Rule

Q:

In a camp, there is a meal for 120 men or 200 children. If 150 children have taken the meal, how many men will be catered to with remaining meal?

A) 50 B) 40
C) 30 D) 20
 
Answer & Explanation Answer: C) 30

Explanation:

There is a meal for 200 children. 150 children have taken the meal.

 

Remaining meal is to be catered to 50 children.

 

Now, 200 children = 120 men.

 

50 children = 12020050 =30men

Report Error

View Answer Report Error Discuss

Filed Under: Chain Rule

Q:

 4 mat-weavers can weave 4 mats in 4 days. At the same rate, how many mats would be woven by 8 mat-weavers in 8 days?

A) 16 B) 12
C) 8 D) 4
 
Answer & Explanation Answer: A) 16

Explanation:

Let the required number of bottles be x.

 

More weavers, More mats (Direct Proportion)

 

More days, More mats (Direct Proportion)

 

 

weavers  4:8} :4:xdays        4:8}:4:x 

4 x 4 x x = 8 x 8 x 4

 

=> x = 8*8*44*4

 

=> x = 16.

Report Error

View Answer Report Error Discuss

Filed Under: Chain Rule

Q:

A fort had provision of food for 150 men for 45 days. After 10 days, 25 men left the fort. The number of days for which the remaining food will last, is:

A) 29/5 B) 37/4
C) 42 D) 54
 
Answer & Explanation Answer: C) 42

Explanation:

After 10 days : 150 men had food for 35 days.

 

 

 

Suppose 125 men had food for x days.

 

 

 

Now, Less men, More days (Indirect Proportion)

 

 

 

 125 : 150 :: 35 : x    =>    125 x x = 150 x 35

 

 

 

 =>

 

 

 

=> x = 42.

Report Error

View Answer Report Error Discuss

Q:

If the cost of x metres of wire is d rupees, then what is the cost of y metres of wire at the same rate?

A) Rs. (xy/d) B) Rs. (xd)
C) Rs. (yd) D) Rs. (yd/x)
 
Answer & Explanation Answer: D) Rs. (yd/x)

Explanation:

Cost of x metres = Rs. d.

Cost of 1 metre = Rs.(d/x)

Cost of y metres = Rs.[(d/x).y] = Rs.(yd/x)

Report Error

View Answer Report Error Discuss

Filed Under: Chain Rule