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Q:

$\frac{7}{8} o f 448 + \frac{6}{7} o f 3374 = ?$

A) 3084	B) 3184
C) 3584	D) None of these

Answer & Explanation Answer: D) None of these

Explanation:

$\frac{7}{8} x 448 + \frac{6}{7} x 3374 = > 392 + 2892 = > 3284$

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Filed Under: Simplification
Exam Prep: CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk

Q:

$2660 o f \frac{1}{7} o f \frac{1}{2} o f \frac{1}{9.5} o f \frac{1}{2} = ?$

A) 1	B) 10
C) 0.1	D) 100

Answer & Explanation Answer: B) 10

Explanation:

$\frac{1}{7} x \frac{1}{2} x \frac{1}{9.5} x \frac{1}{2} x 2660 = \frac{2660}{266} = 10$

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Filed Under: Simplification
Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Bank Clerk , Bank PO

Q:

The age of a man is 4 times of his son. Five years ago, the man was nine times old as his son was at that time. The present age of man is?

Answer

Let the son's age be x years and the father's age be 4x years

$\Rightarrow (4x-5)=9(x-5)$

5x = 40

x = 8

$\inline \therefore$ present age of the father = $\inline 4x$ = $\inline 4\times 8$ = 32 years

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Subject: Problems on Ages

Q:

The Average age of 12 men is decreased by one year when two of them having ages 28 years and 32 years are replaced by two women of same age . The age of a women is?

Answer

Suppose age of each women be W and average age of 12 men be x

$\therefore \frac{12x-28-32+2W}{12}=x-1$

$\therefore W=24$

Hence , each woman's age = 24 years

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Subject: Problems on Ages

Q:

8 years ago Rama's mother was five times older than her daughter. After 8 years the mother will be twice older than her daughter . Find the present age of Rama?

Answer

Let Rama's age 8 years ago be x years and mother's age 8 years ago be 5x

$\Rightarrow 2(x+16)= 5x+16$

$2x+32=5x+16$

$3x=16$

$x=\frac{16}{3}$ years

Hence, present age of Rama = $x+8=\frac{16}{3}+8=\frac{40}{3}=13\frac{1}{3}$ years

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Subject: Problems on Ages

Q:

Ten years ago, A was half of B in age. If the ratio of their present ages is 3:4, then what will be the total of their present ages?

Answer

Let A's age 10 years ago be x years

Then B's age 10 years ago be 2x yeats

$\inline \Rightarrow \frac{x+10}{2x+10}=\frac{3}{4}$

$\inline \Rightarrow 4(x+10)=3(2x+10)$

$\inline \Rightarrow x=5$

$\inline \therefore$ Total of their present ages = $x+10+2x+10$

= $3x+20$

= 35 years

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Subject: Problems on Ages

Q:

One year ago the ratio between Mohan and Ashok's age was 4:3 after one yerar the rato of their ages will be 5:4 . what is the sunm of their present ages in years.

Answer

Let their ages one year ago be 4x and 3x years

$\Rightarrow \frac{4x+2}{3x+2}=\frac{5}{4}\Rightarrow 4(4x+2)=5(3x+2)$

$\Rightarrow x=2$

$\therefore$ Sum of their present ages =(4x +1+3x+1) = 16 years.

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Subject: Problems on Ages

Q:

July 14 is celebrated every year as a national holiday in France. On this day in 1789,

A) The member of the third estate declared themselves the National Assembly	B) Workers, peasants and other non propertied classes were given political rights
C) Napoleon become the Emperor	D) The fall of Bastille took place

Answer & Explanation Answer: D) The fall of Bastille took place

Explanation:

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Filed Under: World History

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