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Q:

Who was apointed as ICAI ( Institute of Chartered Accountants of India) president in 2017 ?

A) Naveen N D Gupta B) Nilesh Shivji Vikamsey
C) Rajesh Kakkar D) Bhavraj Singh
 
Answer & Explanation Answer: B) Nilesh Shivji Vikamsey

Explanation:

The Institute of Chartered Accountants of India (ICAI) elected Nilesh Shivji Vikamsey as president and Naveen N D Gupta as vice-president. They have been elected for the year 2017-18. Vikamsey, who served as vice-president, has been a member of the ICAI since 1985. Gupta has been a chartered accountant for more than 20 years.

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Filed Under: General Awareness
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Q:

At the university entrance exam, a candidate is admitted according to whether he has passed or failed the test. Of the candidates who are really capable, 80 % pass the test and of the incapable, 30 % pass the test. Given that 40 % of the candidates are really capable, then the proportion of the really capable students who can pass the test to the total students who can pass is about ?

A) 11/24 B) 1/5
C) 16/25 D) 6/5
 
Answer & Explanation Answer: C) 16/25

Explanation:

If there are total 100 candidates,
40 candidates are really capable and
60 candidates are incapable.
Of the candidates who are really capable = 80%
40*(80/100)=32 pass the test and
of the incapable= 30%
60*(30/100)=18 pass the test.
Total candidates who passed the test = 32+18 = 50
The proportion of the really capable students who can pass the test to the total students who can pass = 32/50 = 16/25.

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Filed Under: Ratios and Proportions
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Q:

One paper is equally folded 35 times, then what is the new thickness of the paper ?

A) T(2^50) B) 50T
C) 2 x 50 T D) T/50
 
Answer & Explanation Answer: A) T(2^50)

Explanation:

Let initial thickness of the paper be 'T'
after first fold it will be '2T' = 21T
after second fold it will be '4T' = 22T 
after 50th fold it will be T x (250T)

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Filed Under: Logic
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Q:

Fill in the blank with an appropriate word from the following options.

Usually the room tariff in this hotel is higher. At present, it is low because of the------- season.

A) Peak B) Off
C) Down D) Slow
 
Answer & Explanation Answer: B) Off

Explanation:

Season can be either at peak or off.
Presently it is low, that is because of OFF season.

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Filed Under: Analogy
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Q:

Question :

In a cricket team, the average age of eleven players in 28 years. What is the age of the captain?

Statements :

a. The captain is eleven years older than the youngest player.

b. The average age of 10 players, other than the captain is 27.3 years.

c. Leaving aside the captain and the youngest player, the average ages of three groups of three players each are 25 years, 28 years and 30 years respectively.

A) All a,b and c follows B) Only a and c follows
C) Either b alone or a & b follows D) None
 
Answer & Explanation Answer: C) Either b alone or a & b follows

Explanation:

From statement (b)
Average of 11 players = 11 x 28 = 308
Average of 10 players = 10 x 27.3 = 273
Age of captain = 308 - 273 = 35.

From the Statement (a) we can say that captain's age (C) = y + 11 ...(1) where y-youngers age
From the statement (c),the averge age of 3groups of 3players each was given,
It means total 9 players age was given indirectly,
1st group: 25 x 3 = 75
2nd group: 28 x 3 = 84
3rd group: 30 x 3 = 90
Total  is 75 + 84 + 90 = 249
Now {C + Y + (9 players age sum)}/11 = 28
Y + 11 + Y + (249) = 28 x 11=308
2Y+260=308
2Y = 308-260 = 40 ==> Y=24 ==> C(captain's age)= Y+11 = 24+11 = 35

Therefore, statement b alone or a & c only is the answer.

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Filed Under: Statement and Conclusions
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Q:

In a town of 500 people, 285 read Hindu and 212 read Indian Express and 127 read Times of India, 20 read Hindu and Times of India and 29 read Hindu and Indian Express and 35 read Times of India and Indian express . 50 read no news paper . Then how many read only one paper ?

A) 123 B) 231
C) 312 D) 321
 
Answer & Explanation Answer: D) 321

Explanation:

No. of people who read Hindu = 285
No. of people who read TOI = 127
No. of people who read IE = 212
Now,
No. of people who read Hindu and TOI both is = 20
No. of people who read TOI and IE both is = 35
No. of people who read Hindu and IE both is = 29
Let No. of people who read Hindu , TOI and IE all is = x ;
So, only Hindu is = 285-20-29-x = 236-x ;
Only TOI is = 127-20-35-x = 72-x ;
Only IE is = 212-35-29-x = 148-x ;
Now, 236-x + 72-x + 148-x + 20 + 29 + 35 + x + 50 = 500 590 -2x = 500
So, x = 45 this is the value who read all the 3 dailies.
So, No. of people who read only one paper is = 236-45 + 72-45 + 148-45 = 191 + 27 + 103 = 321.

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Filed Under: Logical Venn Diagram
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Q:

Avanthi’s age is 1/6th of her father’s age. Her father’s age will be twice of Kapil’s age after 10 years. If Kapil’s eighth birthday was celebrated two years ago, then what is Avanthi’s present age ?

A) 6 years B) 4 years
C) 7 years D) None
 
Answer & Explanation Answer: D) None

Explanation:

As given Kapil's 8th birthday was celebrated 2 years ago,

Kapil’s present age = 8 + 2 = 10 years.

Father's age is twice of Kapil’s age after 10 years.
=> F + 10 = 2 (K + 10) = 2 (10+ 10)
F = 30years,

Avanthi's age =1/6(F) = 30/6 = 5 years.

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Filed Under: Problems on Ages
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Q:

A person is asked to put in a basket one apple when ordered 'one', one guava when ordered 'two', one orange whe ordered 'three' and is asked to take out from the basket one apple and one guava both when ordered 'four'. The ordered sequence executed by the person is as follows :

1 2 3 3 2 1 4 2 3 1 4 2 2 3 3 1 4 1 1 3 2 3 4


1. How many apples will be there in the basket at the end of the above order sequence ?
      (a) 4     (b) 3     (c) 2    (d) 1


2. How many fruits will be there in the basket at the end of the above order sequence ?
      (a) 13   (b) 17   (c) 9    (d) 11

Answer

1. Answer (c)


Each time we order 1, one apple is added to the basket but each time when 4 is ordered, one apple is removed from it.


Required number of apples = number of 1's - number of 4's = 6 - 4 = 2


2. Answer (d)


Each time we order 1, 2 or 3, one fruit is added to the basket but when ever we order 4, two fruits are removed from it.


Required number = Number of 1's + Number of 2's + Number of 3's - 2 x (Number of 4's)


= 6 + 6 + 7 - (2x4)
= 19 - 8
= 11.

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